我收到来自Jira API的回复,要求将其反序列化为数据模型:

com.atlassian.greenhopper.service.sprint.Sprint@40675167[id=10151,rapidViewId=171,state=CLOSED,name=Sprint 37.1,startDate=2015-07-30T16:00:22.000+03:00,endDate=2015-08-13T16:00:00.000+03:00,completeDate=2015-08-13T14:31:34.343+03:00,sequence=10151]


这实际上是当前要发布的Sprint的信息。
我需要将其反序列化为以下模型:

public class Model
{
    public string name { get; set; }
    ...
}


我已经使用com.atlassian.greenhopper.service.sprint.Sprint@40675167删除了所有不需要的信息,例如Regex pattern \[(.*?)\],所以我在里面有方括号。

现在,我不再完全尝试寻找将这种字符串转换为数据模型的方法。

最佳答案

在Atlassian Answers页面上找到以下thread,该内部Object似乎没有JSON表示形式。如该线程示例中所示:

customfield_10007:[
"com.atlassian.greenhopper.service.sprint.Sprint@a29f07[rapidViewId=<null>,state=CLOSED,name=NORD - Sprint 42,startDate=2013-07-29T06:47:00.000+02:00,endDate=2013-08-11T20:47:00.000+02:00,completeDate=2013-08-14T15:31:33.157+02:00,id=107]",
"com.atlassian.greenhopper.service.sprint.Sprint@769133[rapidViewId=<null>,state=ACTIVE,name=NORD - Sprint 43,startDate=2013-08-14T15:32:47.322+02:00,endDate=2013-08-23T15:32:47.322+02:00,completeDate=<null>,id=117]"
],


响应的确是一个JSON数组,但是该数组本身包含CSV,因此您可以利用以下内容进行解析:

   public class DataObject
    {
        public string id { get; set; }
        public string rapidViewId { get; set; }
        public string state { get; set; }
        public string name { get; set; }
        public string startDate { get; set; }
        public string endDate { get; set; }
        public string completeDate { get; set; }
        public string sequence { get; set; }
    }


    public class Program
    {
        private const string sampleStringData =
            @"[id=10151,rapidViewId=171,state=CLOSED,name=Sprint 37.1,startDate=2015-07-30T16:00:22.000+03:00,endDate=2015-08-13T16:00:00.000+03:00,completeDate=2015-08-13T14:31:34.343+03:00,sequence=10151]";


        static void Main(string[] args)
        {
            var dataObject = new DataObject();

            string[][] splitted;
            var sampleWithNoBrackets = sampleStringData.Substring(1,sampleStringData.Length-2);
            splitted = sampleWithNoBrackets.Split(',').Select(p => p.Split('=')).ToArray();

            dataObject.id           = splitted[0][1];
            dataObject.rapidViewId  = splitted[1][1];
            dataObject.state        = splitted[2][1];
            dataObject.name         = splitted[3][1];
            dataObject.startDate    = splitted[4][1];
            dataObject.endDate      = splitted[5][1];
            dataObject.completeDate = splitted[6][1];
            dataObject.sequence     = splitted[7][1];

            Console.ReadKey();
        }
    }


这是上面的输出:

c# - 将CSV字符串反序列化为C#对象-LMLPHP

关于c# - 将CSV字符串反序列化为C#对象,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/32524313/

10-12 00:49