我正在制作基于极坐标的AI导航系统。目的是将角色移动到某个位置，同时还要远离其路径上可能的障碍物。
该代码在大多数情况下都能正常工作，但是经过测试，我发现了这一点:当播放器，障碍物和角色在X或Y方向或对角线上完全对齐时，角色会卡在障碍物中。当玩家“拥抱”墙壁时，这是最明显的，因为 Actor 的运动 vector 被墙壁夹住，使它们对齐。
单击代码片段中的按钮以查看我的情况。
有办法防止这种情况吗？
const canvas = document.getElementById('canvas');
const ctx = canvas.getContext('2d');
let playerX = 100;
let playerY = 200;
let obstacleX = 200;
let obstacleY = 200;
let actorX = 300;
let actorY = 201;
function loop() {
// Wall clipping
if (actorX > 490) {
actorX = 490;
} else if (actorX < 10) {
actorX = 10;
}
if (actorY > 490) {
actorY = 490;
} else if (actorY < 10) {
actorY = 10;
}
// Vector between player and actor
let vectorPlayerX = playerX - actorX;
let vectorPlayerY = playerY - actorY;
// Vector between obstacle and actor
let vectorObstacleX = obstacleX - actorX;
let vectorObstacleY = obstacleY - actorY;
// Where to move, defaults to player's position
const anglePlayer = Math.atan2(vectorPlayerY, vectorPlayerX);
let moveAngle = anglePlayer;
// If near obstacle, adjust course and try to avoid it
if (Math.sqrt(vectorObstacleX * vectorObstacleX + vectorObstacleY * vectorObstacleY) < 50) {
const angleObstacle = Math.atan2(vectorObstacleY, vectorObstacleX);
moveAngle += anglePlayer - angleObstacle;
}
// Move the vector to desired location
actorX += Math.cos(moveAngle);
actorY += Math.sin(moveAngle);
//Drawing
ctx.clearRect(0, 0, 500, 500);
ctx.beginPath();
ctx.fillStyle = "gray";
ctx.arc(actorX, actorY, 10, 0, Math.PI * 2, true);
ctx.fill();
ctx.beginPath();
ctx.fillStyle = "orange";
ctx.arc(obstacleX, obstacleY, 10, 0, Math.PI * 2, true);
ctx.fill();
ctx.beginPath();
ctx.fillStyle = "blue";
ctx.arc(playerX, playerY, 10, 0, Math.PI * 2, true);
ctx.fill();
requestAnimationFrame(loop);
}
requestAnimationFrame(loop);
function nonAligned() {
playerX = 100;
playerY = 200;
obstacleX = 200;
obstacleY = 200;
actorX = 300;
actorY = 201;
}
function alignedY() {
playerX = 100;
playerY = 490;
obstacleX = 200;
obstacleY = 490;
actorX = 300;
actorY = 490;
}
function alignedBoth() {
playerX = 200;
playerY = 200;
obstacleX = 300;
obstacleY = 300;
actorX = 400;
actorY = 400;
}#options {
position: fixed;
top: 5px;
left: 5px;
}<!DOCTYPE html>
<html>
<body>
<canvas id="canvas" width="500" height="500"></canvas>
<div id="options">
<button onclick="nonAligned()">Spawn non-aligned</button>
<button onclick="alignedY()">Spawn Y aligned</button>
<button onclick="alignedBoth()">Spawn diagonally aligned</button>
</div>
</body>
</html>最佳答案
如果与玩家的 Angular 和障碍物的 Angular 相同，则我们继续前进，因为变量彼此抵消。
moveAngle += anglePlayer - angleObstacle;
如果anglePlayer为117和angleObstacle为117并且moveAngle为117，则得到
117 + 117 -117 = 117 ...
您可能想要这样的东西(伪代码)
moveAngle += anglePlayer + random(90)-45;
或者如果碰到障碍物则向左或向右移动
moveAngle += anglePlayer - 90;
if (random(2)==1 moveAngle += 180
关于javascript - AI跟随并避免与障碍物碰撞，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/53057291/