perl -Mbigrat -E'for (1..100) { $i += 1/3; say int($i), "\t", sprintf "%.55f", $i }'
垃圾邮件有很多警告:
Argument "100/3" isn't numeric in addition (+) at …/site_perl/5.24.1/Math/BigRat.pm line 1939.
在没有
-Mbigrat
的情况下再次运行,以查看sprintf的预期效果。您如何将
Math::BigRat
实例$i
降级为可转换为sprintf
的普通NV?版本:
bigrat
0.47 Math::BigRat
0.2612 最佳答案
我期望Math::BigRat
提供一种获取纯数字的方法,它可以:
as_int
as_float
我插入了
$_
的打印内容以进行调试。$i->as_int()
与int($i)
相同:$ perl -Mbigrat -E'for (1..100) { $i += 1/3; say $_, "\t", int($i), "\t", sprintf "%.55f", $i->as_int() }'
...
99 33 33.0000000000000000000000000000000000000000000000000000000
100 33 33.0000000000000000000000000000000000000000000000000000000
$i->as_float()
乍一看似乎可以正常工作,但我不明白输出结果。所有小数位均为零,每第二行$i
等于$_
:$ perl -Mbigrat -E'for (1..100) { $i += 1/3; say $_, "\t", int($i), "\t", sprintf "%.55f", $i->as_float() }'
...
90 30 30.0000000000000000000000000000000000000000000000000000000
91 30 91.0000000000000000000000000000000000000000000000000000000
92 30 92.0000000000000000000000000000000000000000000000000000000
93 31 31.0000000000000000000000000000000000000000000000000000000
94 31 94.0000000000000000000000000000000000000000000000000000000
95 31 95.0000000000000000000000000000000000000000000000000000000
96 32 32.0000000000000000000000000000000000000000000000000000000
97 32 97.0000000000000000000000000000000000000000000000000000000
98 32 98.0000000000000000000000000000000000000000000000000000000
99 33 33.0000000000000000000000000000000000000000000000000000000
100 33 100.0000000000000000000000000000000000000000000000000000000
这是带有Math::BigRat 0.2614的Perl 5.30.0。
因此,警告已修复,但此解决方案似乎出了点问题。
更新:如无
sprintf
的注释中所要求:$ perl -Mbigrat -E'for (1..100) { $i += 1/3; say $_, "\t", int($i), "\t", $i->as_float() }'
...
90 30 30
91 30 91
92 30 92
93 31 31
94 31 94
95 31 95
96 32 32
97 32 97
98 32 98
99 33 33
100 33 100