以下Python函数导致附件应为“text_file.txt”时被命名为“noname”。如您所见,我已经尝试使用MIMEBase和MIMEApplication的2种不同方法。我也尝试了MIMEMultipart('alternative')无济于事。

def send_email(from_addr, to_addr_list,
              subject, html_body,plain_text_body,
              login,
              password,
              smtpserver='smtp.gmail.com:587',
              cc_addr_list=None,
              attachment=None,
              from_name=None):

    message=MIMEMultipart()

    plain=MIMEText(plain_text_body,'plain')
    html=MIMEText(html_body,'html')

    message.add_header('from',from_name)
    message.add_header('to',','.join(to_addr_list))
    message.add_header('subject',subject)

    if attachment!=None:
        #attach_file=MIMEBase('application',"octet-stream")
        #attach_file.set_payload(open(attachment,"rb").read())
        #Encoders.encode_base64(attach_file)
        #f.close()
        attach_file=MIMEApplication(open(attachment,"rb").read())
        message.add_header('Content-Disposition','attachment; filename="%s"' % attachment)
        message.attach(attach_file)


    message.attach(plain)
    message.attach(html)

    server = smtplib.SMTP(smtpserver)
    server.starttls()
    server.login(login,password)
    server.sendmail(from_addr, to_addr_list, message.as_string())
    server.quit()

我如何调用该函数:
send_email(
           from_addr=from_email,
           to_addr_list=["[email protected]"],
           subject=subject,
           html_body=html,
           plain_text_body=plain,
           login=login,
           password=password,
           from_name=display_name,
           attachment="text_file.txt"
           )

最佳答案

您的标题不正确。 filename是属性而不是字符串。

# Add header to variable with attachment file
attach_file.add_header('Content-Disposition', 'attachment', filename=attachment)
# Then attach to message attachment file
message.attach(attach_file)

关于python - 收到的电子邮件附件为 'noname',我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/20831788/

10-11 22:11