regex - ansible lineinfile模块，用多行替换单行

我有一个ansible play，它的工作原理如下，这里我有两个From条目，它们将被更改为TO条目。
但我只是想知道，在我的例子中，是否有办法用一个名为ntp.conf的文件中的两行替换一行。

---
- name: Play to correct the config for NTP clients
  hosts: all
  remote_user: root
  gather_facts: False

  tasks:
  - name: Changing the ntp server configuration on the client
    lineinfile:
      path: /etc/ntp.conf
      ### line to be searched & matched
      regexp: '{{ item.From }}'
      ### line to be in placed
      line: '{{ item.To }}'
      state: present
      backup: yes
      backrefs: yes

    with_items:
    - { From: 'server ros-ntp minpoll 4 maxpoll 10', To: 'server ros-gw.fuzzy.com minpoll 4 maxpoll 10'}
    - { From: 'server ros-ntp-b minpoll 4 maxpoll 10', To: 'server ros-b-gw.fuzzy.com minpoll 4 maxpoll 10'}

    notify: restart_ntp_service

  handlers:
  - name: restart_ntp_service
    service:
      name: ntpd
      state: restarted

最佳答案

您需要使用blockinfile向ntp.conf添加多行。您可以使用lineinfile将目标行替换为注释，然后使用insertafter的blockinfile参数在其后面添加行。
这是blockinfiledocumentation。
或者，您可以使用两个lineinfile任务并利用insertafter属性。像这样的：

- name: Set NTP server to use ros-ntp-b
  lineinfile:
      path: /etc/ntp.conf
      regexp: 'server ros-ntp-?b? minpoll 4 maxpoll 10'
      line: 'server ros-ntp-b minpoll 4 maxpoll 10'
      state: present
      backup: no

- name: Add NTP server config for ros-ntp-gw
  lineinfile:
      path: /etc/ntp.conf
      regexp: 'server ros-ntp-rw minpoll 4 maxpoll 10'
      line: 'server ros-ntp-gw minpoll 4 maxpoll 10'
      insertafter: 'server ros-ntp-b minpoll 4 maxpoll 10'
      state: present
      backup: yes