php - 在Laravel中创建出勤

好吧..我为业务员创建了一个考勤系统，我的数据库结构是


用户（ID，名称）
出席人数（att_id，user_id，created_at）


这是我用于创建出勤的数据，

$final = array:2 [▼
0 => array:3 [▼
"id" => 6
"name" => "Talha Munshi"
"attendance" => array:4 [▼
  0 => array:3 [▼
    "attendance" => "P"
    "advance" => "0"
    "date" => Carbon {#250 ▼
      +"date": "2017-07-16 08:07:00.000000"
      +"timezone_type": 3
      +"timezone": "Asia/Karachi"
    }
  ]
  1 => array:3 [▼
    "attendance" => "P"
    "advance" => "0"
    "date" => Carbon {#249 ▼
      +"date": "2017-07-17 08:07:00.000000"
      +"timezone_type": 3
      +"timezone": "Asia/Karachi"
    }
  ]
  2 => array:3 [▼
    "attendance" => "A"
    "advance" => "0"
    "date" => Carbon {#248 ▼
      +"date": "2017-07-18 08:07:00.000000"
      +"timezone_type": 3
      +"timezone": "Asia/Karachi"
    }
   ]
   3 => array:3 [▼
    "attendance" => "L"
    "advance" => "0"
    "date" => Carbon {#241 ▼
      +"date": "2017-07-19 08:07:00.000000"
      +"timezone_type": 3
      +"timezone": "Asia/Karachi"
        }
      ]
    ]
  ]
  1 => array:3 [▶]
]

$days_count = 20; //From first till today (20th)

现在，我尝试了一些编码，以垂直格式填充每天的出勤情况，视图中编写的代码是这样的：

<table class="table-responsive table-condensed table-striped table-hover table-bordered">
    <thead>
        <tr>
            <td>Salesman</td>
            <?php for($i = 1; $i <= $days_count; $i++){ ?>
            <td><?php echo $i; ?></td>
            <?php }?>
        </tr>
    </thead>
    <tbody>
        @forelse($final as $attend)
            <tr>
                <td>{{ $attend['name'] }}</td>
                <?php for($i = 1; $i < $days_count; $i++){
                    $make_date = date("Y-m")."-".$i;
                ?>

                <?php foreach($attend['attendance'] as $att){
                    if($att['date'] == $make_date){
                ?>
                <td><?php echo $att['attendance']; ?></td>
                <?php } else{?> <td>-</td> <?php  } }?>
                <?php }?>
            </tr>
            @empty
            <tr><td>No Salesman</td></tr>
        @endforelse
    </tbody>
</table>

但是它给出的答案确实使我的大脑崩溃了。这是当前结果



有人可以帮我这个忙吗？

我通过这个做了$final数组。

$users = User::select('id', 'name')
        ->where('type','LIKE','salesman')
        ->get();
$attendances = Attendance::whereBetween('created_at', [$first_date, $now])
        ->get();
foreach($users as $user)
    {
        $salesman['id'] = $user->id;
        $salesman['name'] = $user->name;

        foreach($attendances as $attendance)
        {
            if($attendance->user_id == $user->id)
            {
                $attend_2['attendance'] = $attendance->attendance;
                $attend_2['advance'] = $attendance->advance;
                $attend_2['date'] = $attendance->created_at;
                $attend[] = $attend_2;
            }

        }
        $salesman['attendance'] = $attend;
        $final[] = $salesman;
    }

必需的输出：应该是什么

最佳答案

您可以将视图更改为

<table class="table-responsive table-condensed table-striped table-hover table-bordered">
  <thead>
    <tr>
      <td>Salesman</td>
      <?php for($i = 1; $i <= $days_count; $i++){ ?>
      <td>
        <?php echo $i; ?>
      </td>
      <?php }?>
    </tr>
  </thead>
  <tbody>
    @forelse($final as $attend)
    <tr>
      <td>{{ $attend['name'] }}</td>
      <?php
        for($i = 1; $i < $days_count; $i++){
          $make_date = date("Y-m")."-".$i;
          $set_attendance_for_day=false;
          $attendance_for_day ="-";
          foreach($attend['attendance'] as $att){
            if($att['date'] == $make_date){
               $attendance_for_day = "P";
            }
          }
      ?>
      <td>
        <?php echo $attendance_for_day; ?>
      </td>

      <?php }?>
    </tr>
    @empty
    <tr>
      <td>No Salesman</td>
    </tr>
    @endforelse
  </tbody>
</table>

**根据评论更新

<table class="table-responsive table-condensed table-striped table-hover table-bordered">
  <thead>
    <tr>
      <td>Salesman</td>
      <?php for($i = 1; $i <= $days_count; $i++){ ?>
      <td>
        <?php echo $i; ?>
      </td>
      <?php }?>
    </tr>
  </thead>
  <tbody>
    @forelse($final as $attend)
    <tr>
      <td>{{ $attend['name'] }}</td>
      <?php
        for($i = 1; $i < $days_count; $i++){
          $make_date = date("Y-m")."-".$i;
          $set_attendance_for_day=false;
          $attendance_for_day ="-";
          foreach($attend['attendance'] as $att){
            if($att['date'] == $make_date){
               $attendance_for_day = "P";
            }
          }
      ?>
      <td>
        <?php echo $attendance_for_day; ?>
        <?php if($i==20){ ?>

          ---------------------------------------------------
          <PLACE YOUR FORM HERE>
          ---------------------------------------------------
        <?php } ?>
      </td>

      <?php }?>
    </tr>
    @empty
    <tr>
      <td>No Salesman</td>
    </tr>
    @endforelse
  </tbody>
</table>

关于php - 在Laravel中创建出勤，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/45205142/