我正在尝试一种从Vector2 []调用时重写GetHashCode()的方法。这段代码会为我知道相等的对象生成非唯一的哈希:我将相同的矩形传递给以下类,并生成了不同的哈希码。

public Shape(Rectangle r)
        {
            edges = new Vector2[4];
            edges[0] = new Vector2(0, 0);
            edges[1] = new Vector2(r.Width, 0);
            edges[2] = new Vector2(r.Width, r.Height);
            edges[3] = new Vector2(0, r.Height);
            Console.Write(edges.GetHashCode() + "\n");
            Position = new Vector2(r.X, r.Y);
        }

Vector2数组只是一堆int。如何为整数列表创建唯一的哈希?

最佳答案

您可以使用如下所示的内容:

public static int CombineHashCodes(params int[] hashCodes)
{
    if (hashCodes == null)
    {
        throw new ArgumentNullException("hashCodes");
    }

    if (hashCodes.Length == 0)
    {
        throw new IndexOutOfRangeException();
    }

    if (hashCodes.Length == 1)
    {
        return hashCodes[0];
    }

    var result = hashCodes[0];

    for (var i = 1; i < hashCodes.Length; i++)
    {
        result = CombineHashCodes(result, hashCodes[i]);
    }

    return result;
}

private static int CombineHashCodes(int h1, int h2)
{
    return (h1 << 5) + h1 ^ h2;

    // another implementation
    //unchecked
    //{
    //    var hash = 17;

    //    hash = hash * 23 + h1;
    //    hash = hash * 23 + h2;

    //    return hash;
    //}
}

10-04 10:26