javascript - removeTodo Action 未从状态中移除

我不确定这里哪里出错了，但是当我触发removeTodo动作时，什么也没有发生。我认为这是我过去的错误，但我无法弄清楚。我以为通过将动作设置为将待办事项作为其有效负载，然后在我的调度中将该动作提供给todo.id，它可以删除所说的id。无法完全弄清楚为什么这行不通。

TodoItem.js

import React, { Component } from 'react';
import { connect } from 'react-redux';
import { removeTodo } from '../actions';
import '../../css/Todo.css';

const mapDispatchToProps = dispatch => {
  return {
      removeTodo: todo => dispatch(removeTodo(todo.id))
    };
  };

const mapStateToProps = state => {
  return {todos: [...state.todos]};
};

class ConnectedTodoItem extends Component {
  render() {
    const {handleToggle, todoId} = this.props;
    const mappedTodos = this.props.todos.map((todo, index) => (
      <div className='todo-item'>
        <span onClick={handleToggle} index={index} id={todoId}>
          {todo.title}
        </span>
        <button type='submit' className='rem-btn' id={todoId} onClick={this.props.removeTodo}>X</button>
      </div>
    ));

    return (
      mappedTodos
    );
  }
}

const TodoItem = connect(mapStateToProps, mapDispatchToProps) (ConnectedTodoItem);

export default TodoItem;

reducers.js

import { ADD_TODO } from '../constants/action-types';
import { REMOVE_TODO } from '../constants/action-types';
import uuidv1 from 'uuid';

const initialState = {
  todos: []
};

const rootReducer = (state = initialState, action) => {
  switch (action.type) {
    case ADD_TODO:
    return {
        ...state,
        todos: [...state.todos,
          {
            title: action.payload.inputValue,
            id: uuidv1()
          }]
    }

    case REMOVE_TODO:
    return {
      ...state,
      todos: [...state.todos.filter(todo => todo.id  !== action.payload)]
    }

    default:
      return state;
  }
}

export default rootReducer;

actions.js

import { ADD_TODO } from '../constants/action-types';
import { REMOVE_TODO } from '../constants/action-types';

export const addTodo = (todo) => (
  {
    type: ADD_TODO,
    payload: todo
  }
);

export const removeTodo = (todo) => (
  {
    type: REMOVE_TODO,
    payload: todo.id
  }
)

最佳答案

乍看之下，问题似乎与您呼叫removeTodo的方式有关

如您所见，该函数接受todo参数，然后从中提取ID。

const mapDispatchToProps = dispatch => {
  return {
    removeTodo: todo => dispatch(removeTodo(todo.id))
  };
};

但是，您没有在此处传递待办事项。

onClick={this.props.removeTodo}

尝试以下方法：

onClick={() => this.props.removeTodo(todo)}

更新，以继续威廉的思路。我将执行以下操作，具体绕过id而不是整个对象。这样一来，您就可以更轻松地了解您要更新的内容。

1）调度功能

const mapDispatchToProps = dispatch => {
  return {
    removeTodo: id => dispatch(removeTodo(id))
  };
};

2）通话功能

onClick={() => this.props.removeTodo(todoId)}

3）行动

export const removeTodo = (id) => (
  {
    type: REMOVE_TODO,
    id
  }
)

4）减速机

case REMOVE_TODO: {
  return {
    ...state,
    todos: state.todos.filter(todo => todo.id  !== action.id)
  }
}

关于javascript - removeTodo Action 未从状态中移除，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/53696005/