Possible Duplicate:
Overriding equals and hashCode in Java
package testpack;
import java.util.HashMap;
import java.util.Iterator;
import java.util.Map;
import java.util.Set;
public class TestEm {
private String company;
private int salary;
TestEm(String company, int salary) {
this.company = company;
this.salary = salary;
}
public static void main(String[] args) {
Map<TestEm, String> map = new HashMap<TestEm, String>();
map.put(new TestEm("abc", 100), "emp1");
map.put(new TestEm("def", 200), "emp2");
map.put(new TestEm("ghi", 300), "emp3");
Set<TestEm> set = map.keySet();
Iterator<TestEm> it = set.iterator();
while (it.hasNext()) {
System.out.println(it.next());
}
**System.out.println(map.get(new TestEm("ghi", 300)));**
}
@Override
public boolean equals(Object o) {
if (o == this)
return true;
if (!(o instanceof TestEm))
return false;
TestEm te = (TestEm) o;
return te.company.equals(company) && te.salary == salary;
}
@Override
public int hashCode() {
int code = 0;
code = salary * 10;
return code;
}
/*
* @Override public String toString() {
*
* return this.company; }
*/
}
输出是
testpack.TestEm@3e8
testpack.TestEm@7d0
testpack.TestEm@bb8
emp3
嗨,我在TestEm类中重写了Object类的某些方法,一切正常,但是前三个输出使用迭代器,然后执行SOP,最后一个简单地使用SOP,我只想知道为什么前三个输出是作为使用迭代器的对象,第四个对象只是将正确的输出作为与键对应的值,我没有覆盖toString(),因此前三个输出是正确的,但是没有toString()时,SOP如何显示正确的输出。
最佳答案
迭代器遍历集合中的对象,而
map.get(new TestEm("ghi", 300))
返回与上述键关联的值。该值为
"emp3"
。