java - Spring JPA无法通过EntityDao

所以我在测试Spring JPA时遇到了这个问题，这是我的代码：

ArticleService：

@Service("articleService")
@Transactional(propagation = Propagation.SUPPORTS, readOnly = true)
public class ArticleServiceImpl implements ArticleService {


private ArticleDao articleDao;

  @Autowired
  public ArticleServiceImpl(ArticleDao articleDao) {
    this.articleDao = articleDao;
  }

  public ArticleServiceImpl() {
  }

  @Transactional(propagation = Propagation.REQUIRED, readOnly = false)
  public void addArticle(Article article) {
    articleDao.saveArticle(article);
  }
}

我的ArticleDao：

@Repository("articleDao")
public class ArticleDaoImpl implements ArticleDao {

  private EntityManager em;

  @PersistenceContext
  public void setEntityManager(EntityManager em) {
    this.em = em;
  }

  // To Save the article detail
  public void saveArticle(Article article) {
    article.setAddedDate(new Date());
    em.persist(article);
  }
}

问题在于在InputDatabaseServiceImpl类中执行那些方法。

public class InputDatabaseServiceImpl implements InputDatabaseService {

public ArticleService articleService;


public InputDatabaseServiceImpl(ArticleService articleService){
    this.articleService= articleService;
}

public int inputArticle(Article article) {
    articleService.saveArticle(article);
    return 0;
}

应用appContext.xml

<context:property-placeholder location="/WEB-INF/database.properties" />

<tx:annotation-driven transaction-manager="transactionManager" />

<!-- Declare a datasource that has pooling capabilities-->
<bean id="dataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource"
destroy-method="close"
p:driverClass="${database.driver}"
p:jdbcUrl="${database.url}"
p:user="${database.user}"
p:password="${database.password}"
p:acquireIncrement="5"
p:idleConnectionTestPeriod="60"
p:maxPoolSize="100"
p:maxStatements="50"
p:minPoolSize="10" />

<!-- Declare a JPA entityManagerFactory-->
<bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" >
<property name="persistenceXmlLocation" value="classpath*:META-INF/persistence.xml"></property>
<property name="persistenceUnitName" value="hibernatePersistenceUnit" />
<property name="dataSource" ref="dataSource"/>
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" >
<property name="showSql" value="true"/>
</bean>
</property>
</bean>

<!-- Declare a transaction manager-->
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactory" />
</bean>
</beans>

每当我从inputArticle调用endpoint类时，我都会在NullPointerExpcetion行中找到articleService.saveArticle(article);

我知道这是要解决的最简单的例外，但是一段时间以来，我一直在苦苦挣扎，我需要帮助。任何人都可以给我一个提示，我想念什么？

最佳答案

发生的情况是未初始化ArticleService属性。

这可能是由于InputDatabaseServiceImpl Bean配置不匹配，还是由于注入依赖项的注释不匹配（如果您的bean是自动装配的）。

尝试这个：

public class InputDatabaseServiceImpl implements InputDatabaseService {


   @Autowired
   public ArticleService articleService;

   public InputDatabaseServiceImpl(){
      //no need of arguments constructor
   }

   public int inputArticle(Article article) {
      articleService.saveArticle(article);
      return 0;
   }

}

要自动装配Bean，此Bean必须提供一个公共的默认构造函数，您的ArticleServiceImpl类没有该构造函数。一种修复形式，它将重构ArticleServiceImpl：

@Service("articleService")
@Transactional(propagation = Propagation.SUPPORTS, readOnly = true)
public class ArticleServiceImpl implements ArticleService {

  @Autowired
  private ArticleDao articleDao;


  public ArticleServiceImpl() {
     //default constructor required for @Autowired
  }

  public ArticleServiceImpl() {
  }

  @Transactional(propagation = Propagation.REQUIRED, readOnly = false)
  public void addArticle(Article article) {
    articleDao.saveArticle(article);
  }
}