我在自学Pro*C，这是一个程序，它用光标穿过数据库中的记录，然后编译并运行。它可以达到“进入GestestID（类型出口终止）>的目的。之后，如果输入整数，则错误为“分段错误（核心转储）”。如果输入了一个字符串，它似乎会立即进入位于
if(nGuest_ID==0)
{
printf("BYE\n");
exit(0);
}
然后打印“再见”，然后退出。由于我仍然熟悉如何声明变量以及如何从SQL传入变量，所以我不确定哪些声明对于这里的故障排除可能是至关重要的，所以我将代码基本上保留在这里。
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
exec sql include sqlca;
// OK - Here we GO
void main()
{
// First, create all the variables that we will need to communicate between
// the "C" program and the database
exec sql begin declare section;
//VARCHAR sLastName[51], sFirstName[51], sHotelName[51], sCheckInDate[12], sRoom[11];
VARCHAR sLastName[51], sFirstName[51], sHotelName[51], sTransDate[11];
//int nDays, nGuest_ID, nCount;
int nGuest_ID, nQuantity, nUnitPrice, nCount, nHotelID, nItemID;
//VARCHAR sInCity[11];
VARCHAR sItemName[31], sTaxable[11];
VARCHAR sUserID[21], sPassword[21];
exec sql end declare section;
/////// begin needs work ///////
// Now define the cursor we will use to get all of the charges that the guest incurred at all hotels
exec sql declare dbGuest cursor for
Select G.Guest_ID, G.Last_Name, G.First_Name, C.Item_ID, C.Item_Name, C.Quantity, C.Unit_Price, C.Trans_Date, H.Hotel_Name, H.Hotel_ID, SI.Taxable
From Hotel H, Charge C, Stay S, Guest G, Sales_Item SI Where
C.Stay_ID=S.Stay_ID And H.Hotel_ID=S.Hotel_ID And G.Guest_ID=S.Guest_ID
And SI.Item_ID=C.Item_ID
Group By S.Guest_ID;
//////// end needs work ///////
// Set up the user-id and password to access my database
// Because we are using the local database on this server
// we don't need to use any database location or SID
strcpy(sUserID.arr,"myusername");
strcpy(sPassword.arr,"mypassword");
sUserID.len=strlen(sUserID.arr);
sPassword.len=strlen(sPassword.arr);
exec sql connect :sUserID identified by :sPassword;
// sqlca.sqlcode is a variable that is set based on the last command sent in to the database
// a value anything other than zero for what we just did (connect to the database) indicates
// a error.
if(sqlca.sqlcode !=0)
{
//printf("Sorry, cannot connect to server, pgm aborted %s\n",sqlca.sqlcode); //correction 2/5/14
printf("Sorry, cannot connect to server, pgm aborted %d\n",sqlca.sqlcode); //change to %d
exit(1);
}
//we made it here, so we were able to open the database correctly
exec sql SELECT COUNT(*) INTO :nCount FROM Guest;
printf ("There are %d Guests.\n",nCount);
for(;;){
// Read in through stdio the Guest we want to query, then set it up do we can use it
printf("Enter a Guest_ID(type exit to terminate)>>\n");
scanf("%d",nGuest_ID);
//Guest_ID.len= strlen(Guest_ID.arr);
if(nGuest_ID==0)
{
printf("BYE\n");
exit(0);
}
printf("%s %s %s %s %d\n","Charge Summary for:", sFirstName.arr, sLastName.arr, " Guest_ID:", nGuest_ID);
//printf("I do not work yet (type exit to terminate)>>\n");
// Open our cursor and begin reading records
exec sql open dbGuest;
for(;;)
{
//exec sql fetch dbGuest into :nGuest_ID, :sLastName, :sFirstName, :sHotelName, :sCheckInDate, :nDays, :sRoom;
exec sql fetch dbGuest into :nGuest_ID, :sLastName, :sFirstName, :nItemID, :sItemName, :nQuantity, :nUnitPrice, :sTransDate, :sHotelName, :nHotelID;
if(sqlca.sqlcode !=0) // If anything went wrong or we read past eof, stop the loop
{
break;
}
// Do the crazy stuff to end the C-Strings
sLastName.arr[sLastName.len] = 0;
sFirstName.arr[sFirstName.len] = 0;
sItemName.arr[sItemName.len] = 0;
sTransDate.arr[sTransDate.len] = 0;
sHotelName.arr[sHotelName.len] = 0;
// Print out the information for this guest
printf("%s %d %s %s \n", "Sales_Item: ", nItemID, " - ", sItemName.arr);
}
// close the cursor and end the program
exec sql close dbGuest ;
}
exit(0);
}
我肯定我犯了一个简单的错误，但我没有发现任何有用的搜索。我在一个服务器上运行这个程序，我没有得到任何调试结果（这是到目前为止我唯一无法解决的主要错误），所以你所拥有的就是我所拥有的。通常C程序会在调试器中运行，但这是ProC，我对整个Oracle ProC调试过程有点不知所措（因为它在远程数据库上运行）。有了这种错误，我通常会怀疑内存分配不当，但我在这里看不到这样的情况。
经历了这些但没有帮助：
Segmentation fault (core dumped) runtime error in C
Not so Useful Error -- Segmentation Fault (Core Dump) in Homework Assignment
Segmentation Fault(core dumped)
Segmentation fault (core dumped) read from stdin
最佳答案
由于nGuest_ID是一个int，在调用scanf()时，您需要提供nGuest_ID的地址：
scanf("%d",&nGuest_ID);
这可能是你正在经历的核心转储的原因，但是，OracleUser也提出了一些很好的建议。
希望能有所帮助。
关于sql - Oracle Pro * C —分段故障(核心已转储)，我们在Stack Overflow上找到一个类似的问题：https://stackoverflow.com/questions/21891044/