我试图在按下Dialog Fragment的元素之一时打开弹出菜单,但是即使按下菜单项之一,也永远不会调用onOptionsItemSelected方法。我该怎么解决?
public class AddSongDialogFragment extends DialogFragment implements View.OnClickListener {
private TextView genreTextview;
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.addsong_layout, container);
//...
genreTextview = (TextView) view.findViewById(R.id.genreTextView);
view.findViewById(R.id.ll_genre_menu).setOnClickListener(this);
genreTextview.setText(R.string.press_to_choose_genre);
return view;
}
//...
public void onClick(View v){
switch(v.getId()) {
case R.id.button2:
dismiss();
mListener.onChoose();
break;
case R.id.ll_genre_menu:
PopupMenu popup = new PopupMenu(getContext(), v);
MenuInflater inflater = popup.getMenuInflater();
inflater.inflate(R.menu.song_genres, popup.getMenu());
popup.show();
break;
}
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
genreTextview.setText(item.getTitle());
Log.d("songo", "item selected");
return true;
}
song_genres.xml
<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
<item android:id="@+id/pop"
android:title="@string/pop"/>
<item android:id="@+id/rock"
android:title="@string/rock" />
...
</menu>
最佳答案
您应将setOnMenuItemClickListener(PopupMenu.OnMenuItemClickListener listener)
设置为popup
就像下面
popup.setOnMenuItemClickListener(new OnMenuItemClickListener() {
@Override
public boolean onMenuItemClick(MenuItem item) {
Log.d("songo", "item selected");
return false;
}
});