我在合并排序算法中将两个数组保持并行时遇到麻烦。
假设我有数组defMergeSort和intMergeSort2。

我想按字典顺序对String defMergeSort进行排序,

String[] defMergeSort = {"Echo", "Alpha", "Charlie", "Beta", "Alpha", "Echo"};


数组intMergeSort2表示与defMergeSort平行的元素位置。 (例如:defMergeSort [0] =与intMergeSort2 [0] = 0的回声,defMergeSort [3] =与intMergeSort2 [3] = 3的Beta)
intMergeSort2将与defMergeSort并行重新排列,尽管没有进行数字排序,

int[] intMergeSort2 = {0,1,2,3,4,5};


最终结果应与此类似(不确定在我的示例中对intMergeSort2 []的并行排序对于defMergeSort []中的重复字符串是否正确):


defMergeSort [0] Alpha = intMergeSort2 [1] 1
defMergeSort [1] Alpha = intMergeSort2 [4] 4
defMergeSort [2] Beta = intMergeSort2 [3] 3
defMergeSort [3]查理= intMergeSort2 [2] 2
defMergeSort [4]回声= intMergeSort2 [0] 0
defMergeSort [5]回声= intMergeSort2 [5] 5


以下合并排序算法可以按字典顺序对defMergeSort进行排序,尽管我无法弄清楚如何使defMergeSort保持如上所述的并行状态:

//mergeSort code found at:
//http://www.buildingjavaprograms.com/code-files/2ed/ch13/MergeSort.java
public static void mergeSort(String[] defMergeSort, int[] intMergeSort2) {
    if (defMergeSort.length > 1) {
        // split array into two halves
        String[] left = leftHalf(defMergeSort);
        String[] right = rightHalf(defMergeSort);
        // recursively sort the two halves
        mergeSort(left, intMergeSort2);
        mergeSort(right, intMergeSort2);
        // merge the sorted halves into a sorted whole
        merge(defMergeSort, intMergeSort2, left, right);
    }
}

// Returns the first half of the given array.
public static String[] leftHalf(String[] defMergeSort) {
    int size1 = defMergeSort.length / 2;
    String[] left = new String[size1];
    for (int i = 0; i < size1; i++) {
        left[i] = defMergeSort[i];
    }
    return left;
}

// Returns the second half of the given array.
public static String[] rightHalf(String[] defMergeSort) {
    int size1 = defMergeSort.length / 2;
    int size2 = defMergeSort.length - size1;
    String[] right = new String[size2];
    for (int i = 0; i < size2; i++) {
        right[i] = defMergeSort[i + size1];
    }
    return right;
}

// Merges the given left and right arrays into the given
// result array.  Second, working version.
// pre : result is empty; left/right are sorted
// post: result contains result of merging sorted lists;
public static void merge(String[] defMergeSort, int[] intMergeSort2,
String[] left, String[] right){
    int i1 = 0;   // index into left array
    int i2 = 0;   // index into right array
    for(int i = 0; i < defMergeSort.length; i++){
        if (i2 >= right.length || (i1 < left.length &&
        left[i1].compareTo(right[i2]) <= 0)) {
            defMergeSort[i] = left[i1];
            i1++;
        } else {
            defMergeSort[i] = right[i2];
            i2++;
        }
    }
}

最佳答案

定义一个包含整数和字符串值的对象,对该对象具有单个数组,并对数组进行排序。



class DataElement {
    final String str;
    final int i;

    //Add constructor here
}

DataElement[] array; // sort this array


请注意,您将需要在DataElement中实现Comparable或为sort方法指定Comparator以便控制排序。

10-01 18:18