在满足特定条件之前，我将尝试获取以下输出。
test_1.jpg test_2.jpg .. test_50.jpg
The solution (if you could remotely call it that) that I have is
fileCount = 0
while (os.path.exists(dstPath)):
fileCount += 1
parts = os.path.splitext(dstPath)
dstPath = "%s_%d%s" % (parts[0], fileCount, parts[1])
但是…这会产生以下输出。
test_1.jpg test_1_2.jpg test_1_2_3.jpg .....etc
The Question: How do I get change the number in its current place (without appending numbers to the end)?
Ps. I'm using this for a file renaming tool.
UPDATE: Using various ideas below, i've discovered a loop that works
dstPathfmt = "%s_%d%s"
parts = os.path.splitext(dstPath)
fileCount = 0
while (os.path.exists(dstPath)):
fileCount += 1
dstPath = parts[0]+"_%d"%fileCount+parts[1]
最佳答案
保持dstPath类似于“test_%d.jpg”可能是最简单的，只需通过不同的计数即可：
dstPath = "test_%d.jpg"
i = 1
while os.path.exists(dstPath % i):
i += 1
dstPath = dstPath % i # Final name