java - JPA Spring-过滤日期

是否可以过滤日期？例如，我只想选择最近30天的数据？
选择应该在现在和现在之间-30天之间。
我希望没有查询的解决方案。

@Service
public class PersonService {

   @Autowired
   private PersonRepository personRepository;
   public Stream<Person> all(Person mysearch){
       return personRepository
              .findAll(Example.of(mysearch))
              .stream()
              .map(Person::fromPerson);
  }
}

class 人员:

public class Person {

    public Integer index;
    public String firstname;
    public String lastname;
    @JsonFormat(pattern="dd.MM.yyyy")
    public Date exdate;
    public String insnr;

    private Person(Integer index, String firstname, String lastname, Date exdate, String insnr){
        this.index=index;
        this.firstname=firstname;
        this.lastname=lastname;
        this.exdate=exdate;
        this.insnr=insnr;
    }

    public static Person fromPerson(Person person){
        return person == null ? null : new Person(person.getIndex(), person.getFirstname(), person.getLastname(), person.getExdate(), person.getInsnr());
    }
}

控制器:

@Autowired
   private PersonService personService;
   @RequestMapping(value="/person/list/**")
   public List<Person> loadPersonList(
                   @RequestParam(value = "insnr" ,required=false) String insnr) throws ParseException {
       mysearch.setInsnr(insnr);
       return personService.all(mysearch).collect(Collectors.toList());
   }

最佳答案

Calendar cal = Calendar.getInstance();
cal.setTime(dateInstance);
cal.add(Calendar.DATE, -30);
Date dateBefore30Days = cal.getTime();
 public Stream<Person> all(Person mysearch){
       return personRepository
              .findAll(Example.of(mysearch)).stream().filter(person -> person.getExdate().compareTo(dateBefore30Days) > 0)
                .map(Person::fromPerson)
                .findAny()
                .orElse(""); }