我正在使用一个旧数据库,其中表A由3个组合键组成,表B由2个复合键组成,这与表A中的两个组合键相同

OnesolPeNames

class OnesolPeNames implements Serializable {

    static mapping = {
        table "ONESOL_pe_names"

        id composite: ["division", "peid"]

        columns{
            division column: 'division', length: 8, sqlType: "char"
            peid column: 'pe_id', length: 12, sqlType: "char"
            peNameU column: 'pe_name_u', length: 50, sqlType: "char"
        }
    }

    static hasMany = [ recoverySetups : RecoverySetup]

    ....

恢复设置
class RecoverySetup implements Serializable {

    static mapping = {
        table "recovery_setup"

        id composite: ["division", "peid", "orgkey"]

        columns {
            division column: 'division', length: 10, sqlType: "char"
            peid column: 'peid', length: 12, sqlType: "char"
            orgkey column: 'org_key', length: 8, sqlType: "char"

            oneSolName column: ['division', 'peid']


        }
    }

    static belongsTo = [oneSolName: OnesolPeNames]

    ....

我正在尝试像这样访问OnesolPeNames。

recoverySetup.onesolPeNames.peNameU。

我收到以下错误



我将oneSolName列设置为['division', 'peid']onesol_pe_names_division,onesol_pe_names_peid来自哪里?

难道我的组合密钥既是PK的一部分,又起着FK的作用,被称为“派生身份”?

最佳答案

我有一个类似的问题,我以这种方式解决了映射表:

class RecoverySetup implements Serializable {

    static mapping = {
        table "recovery_setup"
        id composite: ["division", "peid", "orgkey"]
        columns {
            orgkey column: 'org_key', length: 8, sqlType: "char"

            oneSolName {
                column name: 'division'
                column name: 'peid'
            }
        }
        oneSolName updateable: false, insertable: false
    }

    static belongsTo = [oneSolName: OnesolPeNames]
    ...
}

10-01 05:43