我正在创建一个具有ManyToOne关系的JPA实体。为什么在child.setParent(parent);
期间使用flush()
会导致以下失败:
org.apache.openjpa.persistence.ArgumentException: Missing field for property "parent_id" in type "class test.ChildPrimaryKey".
失败的测试代码:
Parent parent = new Parent();
Child child = new Child();
ChildPrimaryKey childPrimaryKey = new ChildPrimaryKey();
childPrimaryKey.setLookupId(1);
child.setId(childPrimaryKey);
child.setParent(parent); // <-- FAIL because of this
// Begin transaction
entityManager.clear();
entityManager.getTransaction().begin();
LOGGER.info("Persisting parent without child.");
entityManager.persist(parent);
LOGGER.info("Updating parent with child.");
childPrimaryKey.setParentId(parent.getId());
parent.getChildren().add(child);
entityManager.merge(parent);
// Fail happens at flush
entityManager.flush();
实体:
@Embeddable
public class ChildPrimaryKey {
@Column(name = "lookup_id")
private int lookupId;
@Column(name = "parent_id")
private long parentId;
}
@Entity
@Table(name = "child")
public class Child {
@EmbeddedId
private ChildPrimaryKey id;
@MapsId("parent_id")
@ManyToOne
private Parent parent;
}
@Entity
@Table(name = "parent")
public class Parent {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "id")
private long id;
@OneToMany(mappedBy = "parent", cascade = CascadeType.ALL, fetch = FetchType.EAGER)
private List<Child> children;
}
如果删除
child.setParent(parent);
语句,则我的代码通过。使用OpenJPA 2.2.2 最佳答案
我相信您的MapsId
应该基于您所提供的类结构为@MapsId("parentId")
。 MapsId
的值是一个属性,而不是列名。