java - 获取QuerySyntaxException:意外 token

是的，我知道有一些关于此错误的帖子，但是em都没有帮助我。我的hql查询出现此错误：

@SuppressWarnings("unchecked")
@Override
public List<StaffRequest> getStaffLeaveRequest(String userID, Date startDate, Date endDate)
{
    Session currentSession = sessionFactory.getCurrentSession();

    List<StaffRequest> results =
    currentSession.createQuery("select new com.timesheet_Webservice.CustomEnity.StaffRequest(lr.leave_ID, lr.leave_Employee, concat(s.staff_First_Name, ' ', s.staff_Last_Name), "
            + "(lr.leave_Days*8.5), lr.leave_Comments, '1805', concat(pro.project_Pastel_Prefix, ' - ', pro.project_Description), lr.leave_Start, lr.leave_End, lr.leave_IsApproved, "
            + "(select lt.leaveType_Description from LeaveType lt where lt.leaveType_ID = lr.leave_Type)) "
            + "from Staff s, Leave lr, Project pro "
            + "where lr.leave_Employee, = s.staff_Code and pro.project_Code = 1805 and lr.leave_Approved = :userID, and lr.leave_IsApproved = 0 and s.staff_IsEmployee <> 0 "
            + "and lr.leave_Start between :startDate and :endDate "
            + "order by concat(s.staff_First_Name, ' ', s.staff_Last_Name)")
                                .setParameter("userID",userID).setParameter("startDate", startDate).setParameter("endDate", endDate).getResultList();

    return results;
}

我不知道是什么问题。我尝试仔细地重新键入查询，我尝试遵循一些可行的类似查询的格式，但仍然没有任何效果。请帮忙

更新：
在@Joakim Danielson更正后，完整的错误如下

{"status":400,"message":"org.hibernate.hql.internal.ast.QuerySyntaxException:
            unexpected token: , near line 1, column 665 [select new com.timesheet_Webservice.CustomEnity.StaffRequest(lr.leave_ID, lr.leave_Employee, concat(s.staff_First_Name, ' ', s.staff_Last_Name),
         (lr.leave_Days*8.5), lr.leave_Comments, '1805', concat(pro.project_Pastel_Prefix, ' - ', pro.project_Description),
    lr.leave_Start, lr.leave_End, lr.leave_IsApproved, (select lt.leaveType_Description from com.timesheet_Webservice.entity.LeaveType lt where lt.leaveType_ID = lr.leave_Type)) from com.timesheet_Webservice.entity.Staff s,
    com.timesheet_Webservice.entity.Leave lr, com.timesheet_Webservice.entity.Project pro where lr.leave_Employee = s.staff_Code and pro.project_Code = 1805 and lr.leave_Approved = :userID,
and lr.leave_IsApproved = 0 and s.staff_IsEmployee <> 0 and lr.leave_Start between :startDate and :endDate order by concat(s.staff_First_Name, ' ', s.staff_Last_Name)]","timeStamp":1548935385459}

最佳答案

“其中lr.leave_Employee，= s.staff_Code”，删除逗号

where lr.leave_Employee = s.staff_Code

您在“ lr.leave_Approved =：userID”中遇到第二个逗号错误

lr.leave_Approved = :userID

注意，在错误消息中，您具有unexpected token: , near line 1, column 665，因此，如果将错误消息中打印的查询粘贴到文本编辑器中，并删除换行符和多余的空格，则会在665列（或位置）中找到错误。

脱离主题，但我建议您学习在查询中使用JOIN的知识，这样可以大大提高可读性