我怎么能把每个月的所有日子都排成这样
$dateStart = "2016/12/14";
$dateFin = "2017/04/21"
[2016/12/14 - 2016/12/31] => 17 days
[2017/01/01 - 2017/01/31] => 31 days
[2017/02/01 - 2017/02/28] => 28 days
[2017/03/01 - 2017/03/30] => 31 days
[2017/04/01 - 2017/04/21] => 21 days
最佳答案
您可以使用函数cal_days_in_monthplus datetime类:
<?php
$dateStart = new DateTime("2016/12/14");
$dateFin = new DateTime("2017/04/21");
$firstDay = $dateStart->format('Y/m/d');
$lastDay = $dateStart->format('Y/m/t');
$totalMonths = $dateStart->diff($dateFin)->m + ($dateStart->diff($dateFin)->y*12);
$result = [];
for ($i = 0; $i <= $totalMonths; $i++)
{
if ($i != 0){
$dateStart->modify('first day of next month');
$firstDay = $dateStart->format('Y/m/d');
$dateStart->modify('last day of month');
$lastDay = $dateStart->format('Y/m/t');
}
$nextDate = explode('/', $firstDay);
$totalDays = cal_days_in_month(CAL_GREGORIAN, $nextDate[1], $nextDate[2]);
if ($i == 0){
$totalDays -= $dateStart->format('d');
} else if ($i == $totalMonths) {
$totalDays = $dateFin->format('d');
}
$result["$firstDay - $lastDay"] = $totalDays;
}
var_dump($result);
缺乏进步,但能满足你的要求。
程序改进,检查如下:
$dateStart = new DateTime("2016/12/14");
$dateFin = new DateTime("2017/04/21");
$totalMonths = $dateStart->diff($dateFin)->m + ($dateStart->diff($dateFin)->y*12);
$result = [];
for ($i = 0; $i <= $totalMonths; $i++)
{
if ($i != 0){
$obj = $dateStart->modify('first day of next month');
}
$firstDay = $dateStart->format('Y/m/d');
if ($i == $totalMonths){
$lastDay = $dateFin->format('Y/m/d');
} else {
$lastDay = $dateStart->format('Y/m/t');
}
$firstDayObj = strtotime($firstDay);
$lastDayObj = strtotime($lastDay);
$totalDays = (int) ceil(($lastDayObj - $firstDayObj) / 86400);
$totalDays = ((int) $dateStart->format('d') == 1) ? $totalDays + 1 : $totalDays;
$result["$firstDay - $lastDay"] = $totalDays;
}
var_dump($result);
//array(5) { ["2016/12/14 - 2016/12/31"]=> int(17) ["2017/01/01 - 2017/01/31"]=> int(31) ["2017/02/01 - 2017/02/28"]=> int(28) ["2017/03/01 - 2017/03/31"]=> int(31) ["2017/04/01 - 2017/04/21"]=> int(21) }