我有:

PHP_METHOD(Car, cls_ref)
{
    Car *car;
    //Car2 *obj11;
    Car2 *car2;
    zval* obj11;
    zend_class_entry ce2 = zend_fetch_class("Car2", sizeof("Car2")-1, ZEND_FETCH_CLASS_DEFAULT TSRMLS_CC);


     if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC, "O", &obj11,ce2) == FAILURE) {
        RETURN_NULL();
    }

    car_object *obj = (car_object *)zend_object_store_get_object(
        getThis() TSRMLS_CC);
  /*  car2_object *objj = (car2_object *)zend_object_store_get_object(
        getThis() TSRMLS_CC);
       car2=(objj->car2);
    */
    car = obj->car;
    if (car != NULL) {
        //cout<<"in car 2 ref"<<endl;

        //car2->reference(s);
    //  (car->cls_ref((Car2&)car2));
    car->cls_ref((Car2&)obj11);
    }

}

where void Car::cls_ref(Car2 &obj){...}


我要解决这个问题。我有错误:


  错误:初始化时无法将“ Car2 *”转换为“ zval *”
      /home/vehicles.cc:191:错误:请求从“ zend_class_entry *”转换为非标量类型“ zend_class_entry”(错误发生在我初始化obj11和ce2 =的位置。)

最佳答案

使用API​​ convert_to_object_ex(value)将zval转换为对象。在此,值的类型为** zval。

-高拉夫

关于php - 如何将zval *转换为对象?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/7427750/

10-13 07:24