java - 如何使if语句查看数组是否具有特定的数字和字符并返回 boolean 值

我正在编写一个代码，以查找用户获得的卡片。返回是否为RoyalFlush。

我有一些找到RoyalFlush的代码，但未按预期工作。

这是我的代码；

{
    private Card [] hand;        // the hand of 5 cards

    // the default constructor
    public PokerHand ()
    {
        hand = new Card [5];
    }

    // A constructor to help with testing
    public PokerHand (Card c0, Card c1, Card c2, Card c3, Card c4)
    {
        hand = new Card [5];
        hand[0] = c0;
        hand[1] = c1;
        hand[2] = c2;
        hand[3] = c3;
        hand[4] = c4;
    }

    // This methods fills the hand with cards from the deck.
    // It uses an insertion sort so that the cards are ordered by rank.
    public void fillHand (Deck deck)
    {
        for (int i=0; i<5; i++)
        {
            int j=i-1;
            Card temp = deck.dealCard();
            while (j>=0 && hand[j].getRank() > temp.getRank())
            {
                hand[j+1] = hand[j];
                j--;
            }
            hand[j+1] = temp;
        }
    }

    // PLACE ADDITIONAL METHODS AFTER THIS COMMENT
    public boolean isRoyalFlush()
    {
        boolean royalFlush = false;
        // simplify the name of hand
        Card c0 = hand[0];
        Card c1 = hand[1];
        Card c2 = hand[2];
        Card c3 = hand[3];
        Card c4 = hand[4];
        // if the five cards in this hand have the same suit, it is flush
        if((c0.getSuit() == c1.getSuit()) && (c1.getSuit() == c2.getSuit())
        && (c2.getSuit() == c3.getSuit()) && (c3.getSuit() == c4.getSuit()))
        {
            // if the five cards in this hand consists of ace, king, queen, jack
            // and ten, it is royal
            if((c0.getRank() == 10) && (c1.getRank() == 11) && (c2.getRank() == 12)
            && (c3.getRank() == 13) && (c4.getRank() == 14))
             royalFlush = true;
        }
        return royalFlush;
    }

在另一堂课上，我将需要计算有多少用户获得了RoyalFlush。

if(hand.isRoyalFlush())
                count[0]++;

但计数始终显示为0。

最佳答案

因为您已经检查了具有特定等级的特定卡。每个人只有一张等级。在哪里进行皇家同花顺的命令可以是任何东西。您要检查的是第一张卡是10，第二张是插孔，依此类推。但是在某些情况下，第一张牌是第二张牌是10，依此类推，这将是一次皇家同花顺。

解决方案-在检查皇家同花顺之前，根据等级对卡列表进行排序