c++ - 无符号char *值转换为十六进制

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Convert two ASCII Hexadecimal Characters (Two ASCII bytes) in one byte
                                
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我有一个典型的用例，我需要将无符号char值转换为十六进制。

例如，

unsigned char *pBuffer = (unsigned char *)pvaluefromClient //where pvaluefromclient is received from a client

pBuffer的长度为32个字节，其值如下：

(gdb) p pBuffer
$5 = (unsigned char *) 0x7fd4b82cead0 "EBA5F7304554DCC3702E06182AB1D487"
(gdb) n

步骤1：我需要按以下方式拆分此pBuffer值：

{EB,A5,F7,30,45,54,DC,C3,70,2E,06,18,2A,B1,D4,87 }

步骤2：我需要将上述拆分后的值转换为十进制，如下所示：

const unsigned char pConvertedBuffer[16] = {
    235,165,247,48,69,84,220,195,112,46,6,24,42,177,212,135
};

关于如何实现STEP1和STEP2的任何想法？任何帮助，将不胜感激

最佳答案

这样的事情怎么样：

unsigned char *pBuffer = (unsigned char *)pvaluefromClient //where valuefromclient is received from a client

int i, j;
unsigned char target[16]
for(i=0;i<32;i+=2)
{
   sscanf((char*)&pBuffer[i], "%02X", &j);
   target[i/2] = j;
}