嗨,我使用字符串和航班的哈希图创建了一个名为planeStore的航班商店。因此,我也使用哈希图制作了另一家商店(航空公司商店)。我将planeStore放入AirlineStore。但是我不能让航空公司把飞机打印出来。
我以为可以通过将AirlinesName字符串放入Airlines构造函数中。并在创建Airline航空公司= new Airline(“ PlaneName”)时传递“飞机名称”;这将工作,但没有。
这是我的代码:
航空公司
import java.util.HashMap;
public class Airline
{
private String airlineName;
private HashMap<String, PlaneStore> map;
public Airline(String airlineName)
{
this.airlineName = "";
map = new HashMap<String, PlaneStore>();
}
public void add(PlaneStore plane)
{
map.put(airlineName, plane);
}
public void remove(String flight)
{
map.remove(flight);
}
public void printPlane()
{
System.out.println("\n********Flight List********");
for (PlaneStore plane: map.values()) {
//System.out.println(plane);
// class
// or:
System.out.println(airlineName);
System.out.println(plane.toString());
}
}
}
plane.toString是PlaneStore的toString:
public String toString() {
return "PlaneStore [airlineName=" + airlineName + ", planeMap="
+ planeMap + "]";
}
主程序
import java.util.Scanner;
public class MainApp
{
private Scanner keyboard = new Scanner(System.in);
public static void main(String[] args)
{
new MainApp().start();
}
public void start()
{
Airline airline1 = new Airline("AerLingus");
Airline airline2 = new Airline("Ryan Air");
PlaneStore planeStore = new PlaneStore("Aer Lingus");
PlaneStore planeStore2 = new PlaneStore("Ryan Air");
Flight p1 = new Flight("Aer Lingus","A01", 150.5, 10.5, 500, Flight.AIRPLANETYPE.AIRBUS);
Flight p2 = new Flight("Aer Lingus","B01", 50.3, 1.5, 91, Flight.AIRPLANETYPE.CORPORATE);
Flight p3 = new Flight("Aer Lingus","C01", 12.2, -3.1, 56, Flight.AIRPLANETYPE.AIRBUS);
Flight p4 = new Flight("Ryan Air","D01", 10.5, 1.5, 430, Flight.AIRPLANETYPE.PRIVATE);
Flight p5 = new Flight("Ryan Air","E01", 0.3, 2.1, 101, Flight.AIRPLANETYPE.CORPORATE);
Flight p6 = new Flight("Ryan Air","F01", 2.2, -3, 291, Flight.AIRPLANETYPE.AIRBUS);
planeStore.add(p1);
planeStore.add(p2);
planeStore.add(p3);
planeStore.print();
airline1.add(planeStore);
airline1.add(planeStore);
airline1.add(planeStore);
airline1.printPlane();
planeStore2.add(p4);
planeStore2.add(p5);
planeStore2.add(p6);
airline2.add(planeStore2);
airline2.add(planeStore2);
airline2.add(planeStore2);
airline2.printPlane();
}
}
最佳答案
您的Airline
构造函数收到一个String
参数,但是您没有将Airline类的实例变量airlineName
分配给该参数。您只是将airlineName
设置为“”。
public Airline(String airlineName)
{
this.airlineName = "";
map = new HashMap<String, PlaneStore>();
}
你的意思是:
public Airline(String airlineName)
{
this.airlineName = airlineName;
map = new HashMap<String, PlaneStore>();
}
在代码中进一步查看,似乎每个
Airline
类将具有一个map
,但是您只向该映射添加了一个键以及值PlaneStore
。因此,对于每个map
类中的每个Airline
,您似乎永远不会拥有两个或多个键。因此,使用map
没有意义,可以使用ArrayList
代替。如果我正确理解了您的目标,则可以将AirLine类简化为以下形式:
public class Airline
{
private String airlineName; // Name of the company
private ArrayList <PlaneStore> planeStore;
public Airline(String airlineName)
{
this.airlineName = airlineName;
map = new ArrayList<PlaneStore>();
}
public void add(PlaneStore plane){ planeStore.add(plane);}
public void printPlane()
{
System.out.println(airlineName);
System.out.println("\n********Flight List********");
for (PlaneStore plane: planeStore)
{
System.out.println(plane.toString());
}
}
}