我有一个模型的UpdateView。我想在UpdateView中获取(Newcars模型的)“ car_owner”属性。这是代码。

models.py

class Newcars(models.Model):
    shop_no = models.ForeignKey(Shop, on_delete=models.CASCADE, default=0, related_name='newcars')
    car_name = models.CharField(max_length=250)
    car_owner = models.CharField(max_length=250)

    def get_absolute_url(self):
        return reverse('carapp:index')

    def __str__(self):
        return self.car_name + ' - ' +  self.car_owner


views.py
(这是UpdateView。)

class NewcarUpdate(UpdateView):
    model = Newcars
    fields = ['car_name', 'car_owner']


urls.py(仅urlpatterns的必要部分)

url(r'^newcars/(?P<pk>[0-9]+)/$', views.NewcarUpdate.as_view(), name='newcar-update'),


这是我打算对UpdateView进行的操作,但不了解如何做。

class NewcarUpdate(UpdateView):
    model = Newcars
    fields = ['car_name', 'car_owner']
    #Get the selected newcar object's 'car_owner' attribute.
    #Check if the object's 'car_owner' attribute == "sometext" or not.
    #If matches, only then go the normal update form.
    #If doesn't, redirect to a 404 page.

最佳答案

将此方法添加到您的视图:

def dispatch(self, request, *args, **kwargs):
    if self.get_object().car_owner != "sometext":
        raise Http404('Car owner does not match.')
    return super(NewcarUpdate, self).dispatch(
        request, *args, **kwargs)


您将需要从Http404导入django.http

关于python - 如何在UpdateView(Django)中获取模型实例的属性?,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/39496041/

10-09 17:17