java - 关于SAXparseException:序言中不允许内容

我正在使用glassfish服务器，并且不断出现以下错误：

Caused by: org.xml.sax.SAXParseException: Content is not allowed in prolog.
        at com.sun.enterprise.deployment.io.DeploymentDescriptorFile.read(DeploymentDescriptorFile.java:304)
        at com.sun.enterprise.deployment.io.DeploymentDescriptorFile.read(DeploymentDescriptorFile.java:226)
        at com.sun.enterprise.deployment.archivist.Archivist.readStandardDeploymentDescriptor(Archivist.java:480)
        at com.sun.enterprise.deployment.archivist.Archivist.readDeploymentDescriptors(Archivist.java:305)
        at com.sun.enterprise.deployment.archivist.Archivist.open(Archivist.java:213)
        at com.sun.enterprise.deployment.archivist.ApplicationArchivist.openArchive(ApplicationArchivist.java:813)
        at com.sun.enterprise.instance.WebModulesManager.getDescriptor(WebModulesManager.java:395)
        ... 65 more

最佳答案

检查此链接

http://mark.koli.ch/2009/02/resolving-orgxmlsaxsaxparseexception-content-is-not-allowed-in-prolog.html

简而言之，某些XML文件的前面（<?xml ...?>之前）包含三字节模式（0xEF 0xBB 0xBF），这是UTF-8字节顺序标记。 Java的默认XML解析器无法处理这种情况。

快速而肮脏的解决方案是删除XML文件开头的空白：

String xml = "<?xml ...";
xml = xml.replaceFirst("^([\\W]+)<","<");

请注意，由于String.trim（）仅修剪有限的空白字符，因此还不够。