在下面的示例代码中,“关键部分”具体在哪里?。在“sem_wait()”之后?
#include <stdio.h>
#include <unistd.h>
#include <stdlib.h>
#include <pthread.h>
#include <semaphore.h>
void * thread_snd(void *arg);
void * thread_rcv(void *arg);
sem_t bin_sem;
int number=0;
char thread1[]="A Thread";
char thread2[]="B Thread";
char thread3[]="C Thread";
int main(int argc, char **argv)
{
pthread_t t1, t2, t3;
void *thread_result;
int state;
state = sem_init(&bin_sem, 0, 0);
pthread_create(&t1, NULL, thread_snd, &thread1);
pthread_create(&t2, NULL, thread_rcv, &thread2);
pthread_create(&t3, NULL, thread_rcv, &thread3);
pthread_join(t1, &thread_result);
pthread_join(t2, &thread_result);
pthread_join(t3, &thread_result);
printf("number : %d \n", number);
sem_destroy(&bin_sem);
return 0;
}
void * thread_snd(void * arg)
{
int i;
for(i=0; i<4; i++)
{
while(number != 0)
sleep(1);
number++;
printf("%s, number : %d \n", (char*)arg, number);
sem_post(&bin_sem);
}
}
void * thread_rcv(void * arg)
{
int i;
for(i=0; i<2; i++)
{
sem_wait(&bin_sem);
number--;
printf("%s, number : %d \n", (char*)arg, number);
}
}
最佳答案
实际上,在提供的代码中没有“关键部分”,只有“同步点”,是的,这是通过信号量实现的。临界区也可以用信号量实现,但是线程必须同时使用sem_wait()
和sem_post()
但在大多数情况下,互斥锁用于临界区(如果只有一个线程应该进入它)。