java - 忽略转义-Java

我一直在尝试创建一种用Java编码字符串的方法，但遇到了一个很大的障碍。
我的问题是我无法忽略转义，如\n\u\。（它们也被编码。）
我花了3个小时解决这个问题，这是我的代码。

public Object encode() throws EncodingException {
    String encoded = "";
    if (!isEncoded) {
        int i = 0;
        char[] alpha = (this.value.toString().toCharArray());

        while (!(i >= alpha.length)) {
            i++;
            try {
                if(!(alpha[i - 1] == '\\')){
                    encoded = encoded
                            + SerializeEncoding.encoding.encodings.get(
                                    new String(new char[] { alpha[i - 1] }))
                                    .toString();
                }else{
                    encoded = encoded
                    + alpha[i - 1] + alpha[i];
                    i++;
                }

            } catch (NullPointerException e) {
                encoded = encoded
                        + new String(new char[] { alpha[i - 1] })
                                .toString();
            }

        }
        encodedValue = (Object) encoded;
        isEncoded = true;
        log = encodedValue;
        return (Object) encodedValue;
    } else {
        throw new EncodingException("Already encoded");
    }
}

谢谢你
卷发
另外，如果我遗漏了什么，请告诉我。

最佳答案

我不太清楚您的需求，您可以通过遍历字符串来处理Java中的所有特殊字符

public static void main(String[] args) {
    String before = "test\ntest1\n";
    final StringBuilder result = new StringBuilder();
    final StringCharacterIterator iterator = new StringCharacterIterator(before);
    char character =  iterator.current();
     while (character != CharacterIterator.DONE ){
             // do whatever you want to do with the char... I am just removing the \n
         if (character == '\n') {
             character = iterator.next();
         } else {
             result.append(character);
         }
         character = iterator.next();
     }

    System.out.println(result.toString());
}