我尝试将以下Java类转换为使用泛型的Kotlin。
抽象类MvpViewHolder,M,V:视图?>(itemView:视图):RecyclerView.ViewHolder(itemView){
public abstract class MvpViewHolder<P extends BasePresenter> extends RecyclerView.ViewHolder {
protected P presenter;
public MvpViewHolder(View itemView) {
super(itemView);
}
public void bindPresenter(P presenter) {
this.presenter = presenter;
presenter.bindView(this);
}
public void unbindPresenter() {
presenter = null;
}
}
这是我的科特林尝试
abstract class MvpViewHolder<P : BasePresenter>(itemView: View) : RecyclerView.ViewHolder(itemView) {
protected var presenter: P? = null
fun bindPresenter(presenter: P?): Unit {
this.presenter = presenter
presenter?.bindView(this)
}
fun unbindPresenter(): Unit {
this.presenter = null
}
}
我特别遇到泛型问题。事实证明,在Kotlin中,仅仅执行
MvpViewHolder<P : BasePresenter>
是远远不够的,因为Kotlin要求我们为BasePresenter传递2个类型的参数(我在下面提供了其实现)但是,如果我需要为BasePresenter传递类型参数,那么我的方法签名将如下所示
`abstract class MvpViewHolder<P : BasePresenter<*, *>>(itemView: View) : RecyclerView.ViewHolder(itemView) {`
但是,这对我没有帮助,因为在
presenter.bindView(this)
中,出现类型错误Required: Nothing, Found: MvpViewHolder
我也可以更具体地传递
MvpViewHolder<P: BasePresenter<M, V>, M, V>
,但这意味着无论我叫MvpViewHolder哪里,我都还必须包括2个额外的类型参数。现在必须维护这不仅会很乏味,而且让我很难过。当我使用BasePresenter 时如何摆脱错误,或者避免必须将3个类型参数传递给我的MvpViewHolder类,因此我可以将P定义为
BasePresenter
abstract class BasePresenter<M, V> {
var model: M? = null
var view: WeakReference<V>? = null
fun setM(model: M?): Unit {
this.model = model
if (setupDone()) {
updateView()
}
}
fun bindView(view: V) {
this.view = WeakReference(view)
}
fun unbindView() {
this.view = null
}
abstract fun updateView()
fun view(): V? {
return if (view == null) null else view?.get()
}
fun setupDone(): Boolean {
return view() != null && model != null
}
}
最佳答案
将抽象类更改为以下代码
abstract class MvpViewHolder<P :BasePresenter<P,MvpViewHolder<P>>>(itemView: View) : RecyclerView.ViewHolder(itemView) {
protected var presenter: P? = null
fun bindPresenter(presenter: P) {
this.presenter = presenter
presenter.bindView(this)
}
fun unbindPresenter() {
presenter = null
}
}