ruby - Ruby中的Luhn算法

我一直在尝试用Ruby实现Luhn算法，但是一直收到错误消息nil不能被corereced到Fixnum中。
Luhn算法应该：
从第二个到最后一个数字开始，每隔两个数字翻一番，直到到达第一个数字为止
将所有未接触的数字和两位数相加（两位数需要分开，10变成1+0）
如果总数是10的倍数，则表示您已收到有效的信用卡号码！
这就是我所拥有的：

class CreditCard
  def initialize (card_number)
    if (card_number.to_s.length != 16 )
        raise ArgumentError.new("Please enter a card number with exactly 16 integars")
    end
    @card_number = card_number
    @total_sum = 0
  end

  def check_card
    @new_Array = []
    @new_Array = @card_number.to_s.split('')
    @new_Array.map! { |x| x.to_i }
    @new_Array.each_with_index.map { |x,y|
      if (y % 2 != 0)
        x = x*2
      end
     }
    @new_Array.map! {|x|
     if (x > 9)
        x = x-9
      end
    }
    @new_Array.each { |x|
        @total_sum = @total_sum + x
    }
    if (@total_sum % 10 == 0)
      return true
    else
      return false
    end
  end
end

最佳答案

在你的部门

@new_Array.each_with_index.map { |x,y|
  if (y % 2 != 0)
    x = x*2
  end
}

这些变化不是永久性的另外，正如Victor所写，如果测试失败，您的@new_数组将填充nils。最后

if (@total_sum % 10 == 0)
  return true
else
  return false
end

你可以直接写

@total_sum % 10 == 0

因为ruby方法中的最后一行已经是一个返回。我找到了一个slightly different algorithm并在这里实现了它：

# 1) Reverse the order of the digits in the number.
# 2) Take the first, third, ... and every other odd digit in the reversed digits
#   and sum them to form the partial sum s1
# 3) Taking the second, fourth ... and every other even digit in the reversed digits:
#   a) Multiply each digit by two (and sum the digits if the answer is greater than nine) to form partial sums for the even digits
#   b) Sum the partial sums of the even digits to form s2
# 4) If s1 + s2 ends in zero then the original number is in the form of a valid credit card number as verified by the Luhn test.

def luhn n
  s = n.to_s.reverse
  sum=0
  tmp=0
  (0..s.size-1).step(2) {|k|    #k is odd, k+1 is even
    sum+=s[k].to_i   #s1
    tmp = s[k+1].to_i*2
    tmp = tmp.to_s.split(//).map(&:to_i).reduce(:+) if tmp>9
    sum+=tmp
  }
  sum%10 == 0
end

[49927398716, 49927398717, 1234567812345678, 1234567812345670].each {|num|
  puts "%20s %s" % [num, luhn(num)]
}

#         49927398716 true
#         49927398717 false
#    1234567812345678 false
#    1234567812345670 true

希望这有帮助。