javascript - 如何使用javascript或jquery解析这种类型的字符串？

大家好，我想解析这种类型的字符串:

    {"1":
    [
        {"OrderItemId":832,"ItemId":995,"Price":0},
        {"OrderItemId":833,"ItemId":997,"Price":0},
        {"OrderItemId":834,"ItemId":999,"Price":0}
    ],
    "2":
    [
        {"OrderItemId":835,"ItemId":1008,"Price":0},
        {"OrderItemId":836,"ItemId":1057,"Price":0}
    ]
}

这对我来说非常重要，请大家帮我。

最佳答案

像这样，如果要访问OrderItemId

var test =  {"1":
    [
        {"OrderItemId":832,"ItemId":995,"Price":0},
        {"OrderItemId":833,"ItemId":997,"Price":0},
        {"OrderItemId":834,"ItemId":999,"Price":0}
    ],
    "2":
    [
        {"OrderItemId":835,"ItemId":1008,"Price":0},
        {"OrderItemId":836,"ItemId":1057,"Price":0}
    ]
}

alert(test["1"][0]['OrderItemId']);
alert(test["1"][1]['OrderItemId']);
alert(test["1"][2]['OrderItemId']);

alert(test["2"][0]['OrderItemId']);
alert(test["2"][1]['OrderItemId']);

UPDATE，以未知长度

for (var i=0;i<test["1"].length;i++) {
    alert(test["1"][i]['OrderItemId']);
}

遍历测试
这里有全自动的enojiration

var number, count = 0;
var en = [];
for(number in test) {
    en[count]=number;
    count++;
}
for (var r=0;r<en.length;r++) {
    alert(en[r]);
    for (var i=0;i<test[en[r]].length;i++) {
        alert(test[en[r]][i]['OrderItemId']);
    }
}