我想编写一个SQL查询来划分两个表的计数,然后将它们联接起来以显示关于月份和年份的月份。
我编写了一个查询来对两个表的计数进行除法,但是我不确定如何组合两个表的日期字段,从而出现了月数与除法计数。
select
(a.count_one / b.count_two) as final_count,
a.Months,
b.Months
from
(
select count(*) as count_one, DATE_FORMAT(`date`, "%M %Y") AS `Months`
from first_table
GROUP BY str_to_date(concat(date_format(`first_table `.`date`, '%Y-%m'), '-01'), '%Y-%m-%d')
) a,
(
select count(*) as count_two, DATE_FORMAT(`date`, "%M %Y") AS `Months`
from second_table
GROUP BY str_to_date(concat(date_format(`second_table`.`date`, '%Y-%m'), '-01'), '%Y-%m-%d')
) b
期望的输出:
**Month and Year** **Final_Count**
January 2016 126
February 2016 123
March 2016 45
.... ....
... ....
... ....
最佳答案
您需要加入条件:
select
(a.count_one / b.count_two) as final_count,
a.Months
from
(
select count(*) as count_one, DATE_FORMAT(`date`, "%M %Y") AS `Months`
from first_table
GROUP BY Months)
) a,
(
select count(*) as count_two, DATE_FORMAT(`date`, "%M %Y") AS `Months`
from second_table
GROUP BY Montns)
) b
WHERE a.Months = b.Months
最好学习编写ANSI JOIN:
select
(a.count_one / b.count_two) as final_count,
a.Months
from
(
select count(*) as count_one, DATE_FORMAT(`date`, "%M %Y") AS `Months`
from first_table
GROUP BY Months)
) a
INNER JOIN
(
select count(*) as count_two, DATE_FORMAT(`date`, "%M %Y") AS `Months`
from second_table
GROUP BY Months)
) b
ON a.Months = b.Months