java - Spring Hibernate:值未插入数据库

我似乎无法向表中添加值。没有错误，但是值未插入我的数据库中。提交表格后，不会显示任何错误。

查看控制台后，显示：

Hibernate:
    insert
    into
        referral
        (address, doctor_contact_no, doctor_name, facility_contact_no, facility_type, referral_no, referring_from, referring_to)
    values
        (?, ?, ?, ?, ?, ?, ?, ?)

我已经尝试记录日志，以防万一我的控制器无法读取我提交的表单。

我正在保存的实体/模型的代码片段

@Entity
@Table(name="referral")
public class Referrals {
    @Id
    @Column
    @GeneratedValue(strategy=GenerationType.AUTO)
    private Integer id;

    @Column
    private String referral_no;
    @Column
    private String facility_contact_no;
    @Column
    private String referring_from;
    @Column
    private String referring_to;
    @Column
    private String facility_type;
    @Column
    private String address;
    @Column
    private String doctor_name;
    @Column
    private String doctor_contact_no;'

我的服务类别的代码段

@Service
@Transactional
public class ReferralServicesImpl implements ReferralServices{
    @Autowired
    private ReferralDao referralDao;

    public List<Referrals> list(){
        return referralDao.list();
    }
    public boolean saveReferral(Referrals referral){

        if(referralDao.saveReferral(referral))
            return true;
        else
            return false;
    }
}

控制器方法的代码片段

@RequestMapping(value = "/teleaudiology/referral", method = RequestMethod.GET)
        public ModelAndView showForm() {
            return new ModelAndView("referrals", "referrals", new Referrals());
        }

        @RequestMapping(value = "/teleaudiology/referrals", method = RequestMethod.POST)
        public String submit(@Valid @ModelAttribute("referrals")Referrals referral,
          BindingResult result, ModelMap model) {
            if (result.hasErrors()) {
                return "error";
            }
            System.out.println("referral: "+referral.getDoctor_name());
            if(referralServices.saveReferral(referral))
                return "redirect:../teleaudiology";
            else
                return "redirect:../teleaudiology";
        }

这是ReferralDao类

public interface ReferralDao {
    public boolean saveReferral(Referrals referral);
    public List<Referrals> list();
}

推荐连结

@Repository
@Transactional
public class ReferralDaoImpl implements ReferralDao {
    @Autowired
    SessionFactory session;
    Transaction trans;

    public boolean saveReferral(Referrals referral) {
        // TODO Auto-generated method stub
        //System.out.println("Saving..."+referral.getReferring_to_address());

        trans=session.getCurrentSession().beginTransaction();
        session.getCurrentSession().saveOrUpdate(referral);
        return true;
    }

    public List<Referrals> list() {
        // TODO Auto-generated method stub
        return session.getCurrentSession().createQuery("from Referrals").list();
    }

}

我尝试使用

trans=session.getCurrentSession().getTransaction();

但是导致这个错误

`saveOrUpdate is not valid without active transaction`

servlet-context.xml中的片段

<tx:annotation-driven transaction-manager="transactionManager" />
    <beans:bean id="transactionManager"  class="org.springframework.orm.hibernate4.HibernateTransactionManager">
        <beans:property name="sessionFactory" ref="sessionFactory" />
    </beans:bean>

最佳答案

尝试使用下面的代码

 Session s = sessionFactory.getCurrentSession();
 s.save(object);