我的想法是将图像从一棵完整的树更改为一棵剪切树,然后再转换回完整的树。我的问题是,当我将其更改为剪切后的树的图片时,该图像没有显示,但是当它切换回完整树的图像时,该显示效果很好。这是与问题有关的脚本:

var treeCut;

switch(randomEvent){
        case 1:
         //add a log
         document.getElementById("treeActive").innerHTML = "inActive1";
         treeSpawn=setTimeout(spawnTree,5000);
                 //below is the piece i'm having issues with
         treeCut = document.getElementById("treeButton");
         treeCut.src = function() {
             treeCut.src = "images/treeCut.png";
         }
        break;

//not showing the full switch just the part that is being exicuted.

function spawnTree(){
    document.getElementById("treeActive").innerHTML = "Active";
    count = 0;
    document.getElementById("message").innerHTML = "chop " + count;
    clearInterval(treeSpawn);
        //brings the tree back to original image
    treeCut.src = "images/tree.png";
}


是否存在问题,因为第二张图像需要具有自己的标签?我已经检查,再次检查和三次检查图像是否在正确的位置并正确命名。

最佳答案

您可以直接设置图像的src,例如,更改:

treeCut.src = function() {
    treeCut.src = "images/treeCut.png";
}




treeCut.src = "images/treeCut.png";

09-27 15:29