如何将ArrayList类型的元素传递给方法?我的幼稚尝试遵循以下几行。

public double example( ArrayList<CMyType> list, String type ){

    double out = list.get(0).type // type should be a placeholder for one of the variables which I defined in CMyType
    return out;

}

public class CMyType {
    public double var1;
    public double var2;
}

最佳答案

您要在此处执行的操作:

double out = list.get(0).type // type should be a placeholder for one of


如果不使用反射,则无法实现,如下所示:

public double example( ArrayList<CMyType> list, String type ) {
  CMyClass obj = list.get(0);
  Field field = obj.getClass().getDeclaredField(type);
  Object objOut = field.get(obj);
  // you could check for null just in case here
  double out = (Double) objOut;
  return out;
}


您还可以考虑将CMyType类修改为如下形式:

class CMyType {
  private double var1;
  private double var2;

  public double get(String type) {
    if ( type.equals("var1") ) {
      return var1;
    }
    if ( type.equals("var2") ) {
      return var2;
    }

    throw new IllegalArgumentException();
}


然后从您的代码中调用它,如下所示:

public double example( ArrayList<CMyType> list, String type ) {
  CMyClass myobj = list.get(0);
  return myobj.get(type);
}


更好的解决方案是像这样在Map<String, Double>中使用CMyType

class CMyType {
  private Map<String, Double> vars = new HashMap();

  public CMyType() {
    vars.put("var1", 0.0);
    vars.put("var2", 0.0);
  }

  public double get(String type) {
    Double res = vars.get(type);
    if ( res == null ) throw new IllegalArgumentException();
    return res;
}

09-27 11:44