如何将ArrayList类型的元素传递给方法?我的幼稚尝试遵循以下几行。
public double example( ArrayList<CMyType> list, String type ){
double out = list.get(0).type // type should be a placeholder for one of the variables which I defined in CMyType
return out;
}
public class CMyType {
public double var1;
public double var2;
}
最佳答案
您要在此处执行的操作:
double out = list.get(0).type // type should be a placeholder for one of
如果不使用反射,则无法实现,如下所示:
public double example( ArrayList<CMyType> list, String type ) {
CMyClass obj = list.get(0);
Field field = obj.getClass().getDeclaredField(type);
Object objOut = field.get(obj);
// you could check for null just in case here
double out = (Double) objOut;
return out;
}
您还可以考虑将
CMyType
类修改为如下形式:class CMyType {
private double var1;
private double var2;
public double get(String type) {
if ( type.equals("var1") ) {
return var1;
}
if ( type.equals("var2") ) {
return var2;
}
throw new IllegalArgumentException();
}
然后从您的代码中调用它,如下所示:
public double example( ArrayList<CMyType> list, String type ) {
CMyClass myobj = list.get(0);
return myobj.get(type);
}
更好的解决方案是像这样在
Map<String, Double>
中使用CMyType
:class CMyType {
private Map<String, Double> vars = new HashMap();
public CMyType() {
vars.put("var1", 0.0);
vars.put("var2", 0.0);
}
public double get(String type) {
Double res = vars.get(type);
if ( res == null ) throw new IllegalArgumentException();
return res;
}