我的Wiegand RFID阅读器（26位）有问题。我已经编写了简单的Java应用程序，一切似乎都很好。但是例如读取10次后，它开始移位位。 RPi Raspbian是否因Wiegand时间协议而变慢？
这是示例代码和输出
package classes;
import com.pi4j.io.gpio.GpioController;
import com.pi4j.io.gpio.GpioFactory;
import com.pi4j.io.gpio.GpioPinDigitalInput;
import com.pi4j.io.gpio.PinPullResistance;
import com.pi4j.io.gpio.RaspiPin;
public class Test {
public static char[] s = new char[10000];
static int bits = 0;
public static void main(String[] args) {
// create gpio controller
final GpioController gpio = GpioFactory.getInstance();
// provision gpio pin #02 as an input pin with its internal pull down
// resistor enabled
final GpioPinDigitalInput pin0 = gpio.provisionDigitalInputPin(RaspiPin.GPIO_00, PinPullResistance.PULL_UP);
final GpioPinDigitalInput pin1 = gpio.provisionDigitalInputPin(RaspiPin.GPIO_01, PinPullResistance.PULL_UP);
System.out.println("PINs ready");
Thread th = new Thread(new Runnable() {
@Override
public void run() {
while (true) {
if (pin0.isLow()) { // D1 on ground?
s[bits++] = '0';
while (pin0.isLow()) {
}
}
if (pin1.isLow()) { // D1 on ground?
s[bits++] = '1';
while (pin1.isLow()) {
}
}
if (bits == 26) {
bits=0;
Print();
}
}
}
});
th.setPriority(Thread.MAX_PRIORITY);
th.start();
System.out.println("Thread start");
for (;;) {
try {
Thread.sleep(500);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
protected static void Print() {
for (int i = 0; i < 26; i++) {
System.out.write(s[i]);
}
System.out.println();
bits = 0;
}
}
并输出：
10100100111111110110011011
10100100111111110110011011
10100100111111110110011011
10100100111111110110011011
10100100111111110001101110
10010011111111011001101110
10010011111111011001101110
10010011111111011001101110
10010011111111011001101110
10010011111111011001101110
10010011111111011001101110
最佳答案
您的printf语句可能是导致问题的原因。尝试存储数据并在最后打印。 printf往往很慢（它涉及多个上下文切换）。
另外，似乎您无法检测是否错过了一点。我会说尝试超时，所以如果您没有及时获得26位，请重置计数器。这样一来，您就不会无所事事，最终会得到未对齐的数据。