我正在创建一个swift应用程序,在那里我需要将数据发布到我自己的web服务器。
目前,我的swift代码是这样的。

fileprivate class AlamofireHelper {
     static var Manager : Alamofire.SessionManager = {
        // Create the server trust policies
        let serverTrustPolicies: [String: ServerTrustPolicy] = [
            "192.168.1.243": .disableEvaluation
        ]
        // Create custom manager
        let configuration = URLSessionConfiguration.default
        configuration.httpAdditionalHeaders = Alamofire.SessionManager.defaultHTTPHeaders
        let man = Alamofire.SessionManager(
            configuration: URLSessionConfiguration.default,
            serverTrustPolicyManager: ServerTrustPolicyManager(policies: serverTrustPolicies)
        )
        return man
    }()

}
class UploadHelper
{

    private var _postData = [String:Any]()
    private let almoHelper = AlamofireHelper.Manager
    init(username:String) {
        _postData["username"] = username
        print("Setup")
        submitRequest()
    }

    func submitRequest()
    {
        print("Data is: \(_postData)")
        almoHelper.request("http:/192.168.1.243/networkStorage", method: .post, parameters: _postData, encoding: JSONEncoding.default).responseString { (responce) in
            print("Responce: \(responce)")
        }
    }
}

菲律宾比索:
<?php
    echo "POST: " . var_dump($_POST) . "\n\n\n\n";
    echo "GET: " . var_dump($_GET);
?>

唯一的问题是,当我运行swift代码let helper = UploadHelper(username: iProgram)时,从我的PHP脚本得到以下响应:
Data: ["username": "iProgram"]
Responce: SUCCESS: array(0) {
}
POST:



array(0) {
}
GET:

为什么我的POST和GET变量是空的?我知道GET是空的,因为我只发送POST数据,但是POST不应该显示“username=iProgrammer”之类的内容吗?
最后,这里是我从burp suit捕获的HTTP请求:
GET /networkStorage/ HTTP/1.1
Host: 192.168.1.243
Accept: */*
User-Agent: Network%20Storage/1 CFNetwork/808.2.16 Darwin/16.3.0
Accept-Language: en-gb
Accept-Encoding: gzip, deflate
Connection: close

编辑:
出于某种原因,当我使用下面的代码并更改PHP脚本以显示“GET”变量时,我可以看到它应该发送的数据。
almoHelper.request("http://192.168.1.243/networkStorage", method: .get, parameters: _postData).responseString { (myResponce) in
            let result = myResponce.result
            print("Result is: \(result.value!)")
        }

这是我从burp套件中截获的请求:
GET /networkStorage/?username=iProgram HTTP/1.1
Host: 192.168.1.243
Accept: */*
User-Agent: Network%20Storage/1 CFNetwork/808.2.16 Darwin/16.3.0
Accept-Language: en-gb
Accept-Encoding: gzip, deflate
Connection: close

最佳答案

首先,var_dump不返回任何内容,它会输出结果,因此使用

echo "POST: "; var_dump($_POST); echo "\n\n\n\n";


echo "POST: " . print_r($_POST, true) . "\n\n\n\n";

GET /networkStorage/ HTTP/1.1显示您发出GET请求,而不是POST。此外,您还有错误的编码JSONEncoding.defaul。尝试稍微更改请求代码:
almoHelper.request("http:/192.168.1.243/networkStorage", method: .post, parameters: _postData, encoding: URLEncoding.httpBody).responseString { (responce) in
    print("Responce: \(responce)")
}

如果这不起作用,请尝试将URL从http:/192.168.1.243/networkStorage更改为http:/192.168.1.243/networkStorage/http:/192.168.1.243/networkStorage/index.php
这可能会解决当您向/networkStorage发送请求时的问题,它会向/networkStorage/发送新请求,如从burpsuit捕获的数据所示。

09-27 06:51