为什么我遇到以下异常:
Exception in thread "main" java.io.IOException: Push back buffer is full
at java.io.PushbackInputStream.unread(PushbackInputStream.java:232)
at java.io.PushbackInputStream.unread(PushbackInputStream.java:252)
at org.tests.io.PushBackStream_FUN.read(PushBackStream_FUN.java:32)
at org.tests.io.PushBackStream_FUN.main(PushBackStream_FUN.java:43)
在此代码中:
public class PushBackStream_FUN {
public int write(String outFile) throws Exception {
FileOutputStream outputStream = new FileOutputStream(new File(outFile));
String str = new String("Hello World");
byte[] data = str.getBytes();
outputStream.write(data);
outputStream.close();
return data.length;
}
public void read(String inFile, int ln) throws Exception {
PushbackInputStream inputStream = new PushbackInputStream(new FileInputStream(new File(inFile)));
byte[] data = new byte[ln];
String str;
// read
inputStream.read(data);
str = new String(data);
System.out.println("MSG_0 = "+str);
// unread
inputStream.unread(data);
// read
inputStream.read(data);
str = new String(data);
System.out.println("MSG_1 = "+str);
}
public static void main(final String[] args) throws Exception {
PushBackStream_FUN fun = new PushBackStream_FUN();
String path = "aome/path/output_PushBack_FUN";
int ln = fun.write(path);
fun.read(path, ln);
}
}
更新
认为这是解决方案。 Java资源可以拯救。我做了一些“实验”。事实证明,当我使用指定的缓冲区大小指定
PushbackInputStream
时,它可以工作。 Java资料告诉我:public PushbackInputStream(InputStream in) {
this(in, 1);
}
public PushbackInputStream(InputStream in, int size) {
super(in);
if (size <= 0) {
throw new IllegalArgumentException("size <= 0");
}
this.buf = new byte[size];
this.pos = size;
}
我认为,如果将
PushbackInputStream
与使用默认缓冲区大小的构造函数一起使用,则只能读取单个字节。我读的不止一个字节,因此是个异常(exception)。 最佳答案
默认情况下,PushbackInputStream
仅分配足够的空间以能够为单个字符添加unread()
。如果您希望能够进行更多的回推,则必须在构造时指定容量。
在您的情况下,它看起来像这样:
final PushbackInputStream pis = new PushbackInputStream( inputStream, ln );
关于java - PushbackInputStream:推回缓冲区已满,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/19244142/