尝试使用C来连接字符串(*char),并且有很多分段错误:
void printDateFormat( char *in ) { /* begin function printDateFormat */
char *month; // month by char
int month_int; // month by digit
char *day; // day by char
char *year; // year by char
char *dateToken; // date token in split
char *formatted; // formatted string
dateToken = strtok (in, "/");
month = &dateToken;
formatted = formatted = getMonth(month);
dateToken = strtok (NULL, "/");
day = &dateToken;
formatted = strcat (formatted, day);
formatted = strcat (formatted, ", ");
dateToken = strtok (NULL, "/");
year = &dateToken;
formatted = strcat (formatted, year);
in = *formatted;
} /* End function printDateFormat */
char *getMonth( int d) { /* begin function *getMonth */
switch (d) {
case 1:
return "January";
// break;
case 2:
return "February";
// break;
case 3:
return "March";
// break;
case 4:
return "April";
// break;
case 5:
return "May";
// break;
case 6:
return "June";
// break;
case 7:
return "July";
// break;
case 8:
return "August";
// break;
case 9:
return "September";
// break;
case 10:
return "October";
// break;
case 11:
return "November";
// break;
case 12:
return "December";
// break;
}
} /* End function *getMonth */
printDateFormat()的输入应为另一个字符串,格式为:mm/dd/yyyy…即2013年3月31日。目的是将其转换为:2013年3月31日。
编辑:
以下是我如何进入
printDateFormat
void option1( void ) { /* begin function option1 */
char date[10]; /*user input date string */
printf("\n\nEnter date [Format: MM/dd/yyyy]: ");
fgets(date, 10, stdin);
scanf("%s", &date);
printDateFormat(date);
printf("\n%s", date);
} /* End function option2 */
编辑2:
好吧,做了一些改变但仍然没有骰子…
我的编译器警告如下:
asgn9.c: In function `printDateFormat':
asgn9.c:224: warning: passing arg 1 of `getMonth' makes integer from pointer without a cast
asgn9.c:237: warning: assignment makes pointer from integer without a cast
它们指的是在my
getMonth()
中使用printDateFormat()
。这是我更新的代码,我仍然在同一个地方有一个分段错误…
void printDateFormat( char *in ) { /* begin function printDateFormat */
char *month; // month by char
int month_int; // month by digit
char *day; // day by char
char *year; // year by char
char *dateTkn; // date token in split
char *formatted; // formatted string
dateTkn = strtok (in, "/");
month = dateTkn;
formatted = getMonth(month);
dateTkn = strtok (NULL, "/");
day = dateTkn;
formatted = strcat (formatted, day);
formatted = strcat (formatted, ", ");
dateTkn = strtok (NULL, "/");
year = dateTkn;
formatted = strcat (formatted, year);
in = *formatted;
} /* End function printDateFormat */
char *getMonth( int d) { /* begin function *getMonth */
static char *months[] = {"January", "February", "March", "April", "May",
"June", "July", "August", "September", "October", "November", "December"};
return strcpy(malloc(32), months[d]);
} /* End function *getMonth */
最佳答案
getMonth
返回指向字符串文本的指针。不允许尝试修改它(例如,使用strcat
),这会导致未定义的行为。
我强烈建议使用strftime
来处理打印的格式化日期和/或时间字符串。这不仅可以将格式化代码简化为一行代码,而且还可以在需要时/如果需要时支持本地化结果。
编辑:如果不能使用strftime
,则需要在自己的缓冲区中生成格式化日期,可能使用sprintf
:
char buffer[256];
static const char *months[] = {
"January",
"February",
/* ... */ ,
"November",
"December"
};
sprintf(buffer, "%s %d %d", months[monthnum], day, year);