为了清楚起见,让我的新类(class)是:
class MyInt{
public:
MyInt(int x){theInt = x /10;}
int operator+(int x){return 10 * theInt + x;}
private
int theInt;
};
假设我希望能够定义:
MyInt Three(30);
int thirty = Three;
但是为了得到这个结果,我在写:
MyInt Three(30);
int thirty = Three + 0;
如何从Custom类自动转换为内置类型?
最佳答案
具有类型转换功能:
class MyInt{
public:
MyInt(int x){theInt = x /10;}
int operator+(int x){return 10 * theInt + x;}
operator int() const { return theInt; } // <--
private
int theInt;
};
关于从自定义类到内置类型的转换,我们在Stack Overflow上找到一个类似的问题:https://stackoverflow.com/questions/18534548/