只要输入1我就只想打印learning...
package a;
import java.util.Scanner;
class main extends Thread {
static String n;
Scanner reader = new Scanner(System.in);
public void run() {
n = reader.nextLine();
}
public static void main(String args[]) throws InterruptedException {
(new Thread(new main())).start();
n="5";
System.out.println("1 = ON\n0 = OFF");
while (n.equals("1")) {
System.out.println("Learning..");
}
}
}
最佳答案
如果要停止启动,最好始终保持两个线程,一个用于打印,另一个用于输入。尝试使用打击代码。对我来说很好。
public class ThreadsStop {
static String n="";
class Printer extends Thread{
@Override
public void run() {
while(!n.equals(null)){
try {
Thread.sleep(1000);
if(n.trim().equals("1"))
System.out.println("Learning..");
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
class Starter extends Thread{
@Override
public void run() {
Scanner reader = new Scanner(System.in);
while(true){
System.out.println("1 = ON \n 0 = OFF");
n= reader.nextLine();
}
}
}
public static void main(String[] args) {
new ThreadsStop().start();
}
private void start() {
new Starter().start();
new Printer().start();
}
}