每次出现菜单时,我如何使骰子不重新滚动:
当我按下菜单1选项时,就会发生循环,如何使值保持不变,直到我选择骰子重新滚动:
import java.io.InputStream;
import java.util.Scanner;
class RecordDice {
public static void main(String[] args) {
int dSides, Sides, Choice;
int max = 0, min = 0;
Scanner s = new Scanner(System. in );
Scanner c = new Scanner(System. in );
boolean keepgoing = true;
System.out.println("How many sides should the dice have?");
Sides = s.nextInt();
if (Sides == 4 || Sides == 6 || Sides == 12 || Sides == 20 || Sides == 100) {
while (keepgoing) {
System.out.println("Please make a choice:\n" +
"1 - reroll the dice\n" +
"2 - get the value\n" +
"3 - show the maximum\n" +
"4 - show the minimum");
Dice2 d = new Dice2(Sides);
Choice = c.nextInt();
int Value = d.getValue();
if (Value > max) {
max = Value;
}
if (Value < min) {
min = Value;
}
if (min > max) {
max = min;
}
switch (Choice) {
case 1:
d.reroll();
break;
case 2:
System.out.println("The current value is " + Value);
break;
case 3:
System.out.println("The maximum is " + max);
break;
case 4:
System.out.println("The minimun is " + min);
break;
}
}
}
}
}
最佳答案
您的骰子似乎没有重新滚动。尽管我看不到类Dice2的外观,但我想您的问题是您在循环的每次迭代中都创建了一个新的Dice2。因此,您将失去对上一卷的参考。
将Dice2 d = new Dice2(Sides)放置在while循环之外。它可能看起来像这样:
Dice2 d = new Dice2(Sides);
while (keepgoing) {
System.out.println("Please make a choice:\n" +
"1 - reroll the dice\n" +
"2 - get the value\n" +
"3 - show the maximum\n" +
"4 - show the minimum");
Choice = c.nextInt();
int Value = d.getValue();
if(Value > max){
max = Value;
}
...
希望对您的问题有所帮助! (请注意,此解决方案假定您将Dice的roll值存储在Dice2对象中)