java - 使用冒号时将类@Path注释连接到方法@Path注释

尝试将旧的ERX剩余路由移植到Jerey / JAX-RX时遇到问题。

我正在尝试做这样的事情：

@Path("/v0/user")
@Controller
public class UserRouteController {

    @GET
    public Response getAllUsers(){
    ...
    }

    @GET
    @Path("/{name}")
    public Response getUserWithName(@PathParam("name") String name){
    ...
    }

    @GET
    @Path(":accessibleWithNoRestriction")
    public Response getUsersAccessibleWithNoRestriction(){
        ...
    }

    @GET
    @Path(":withAdminStatus")
    public Response getUsersWithAdminStatus(){
        ...
    }

但是，Jersey不想匹配我的http请求。

blahblah.com/v0/user:accessibleWithNoRestriction

我收到没有方法允许的响应。

最佳答案

我遇到了这篇文章：JAX-RS Application on the root context - how can it be done?

尝试使用此：

@WebFilter(urlPatterns = "/*")
public class PathingFilter implements Filter {
    Pattern[] restPatterns = new Pattern[] {
        Pattern.compile("/v0/user:.*")
    };

    @Override
    public void init(FilterConfig filterConfig) throws ServletException {
        // TODO Auto-generated method stub
    }

    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
        if (request instanceof HttpServletRequest) {

            String path = ((HttpServletRequest) request).getPathInfo();

            for (Pattern pattern : restPatterns) {
                if (pattern.matcher(path).matches()) {
                    String[] segments = path.split(":");
                    String newPath = segments[0] + "/" + segments[1];
                    newPath = ((HttpServletRequest) request).getServletPath() + "/" + newPath;
                    request.getRequestDispatcher(newPath).forward(request, response);
                    return;
                }
            }
        }
        chain.doFilter(request, response);
    }

    @Override
    public void destroy() {
        // TODO Auto-generated method stub
    }
}

然后，您必须将方法中的@Path注释更改为“ / accessibleWithNoRestriction”

这样做是在匹配发生之前更改您的请求的uri。

试试看