我得到了


  GDI +中发生一般错误


呼叫img.Save(path, jpegCodec, encoderParams);时出现异常
这是所有代码:

    private Image img;

    private void button1_Click(object sender, EventArgs e)
    {
        this.img = Image.FromFile(@"path");

        pictureBox1.Image = img;

        if (img.Height < pictureBox1.Height && img.Width < pictureBox1.Width)
        {
            this.pictureBox1.SizeMode = PictureBoxSizeMode.CenterImage;
        }

        Graphics g = Graphics.FromImage(img);

        Font font=new Font("Arial",16);

        SolidBrush brush = new SolidBrush(Color.Black);

        brush.Color = Color.FromArgb(255, 0, 0, 255);

        g.DrawString("myName", font, brush, img.Width - 178, img.Height-105);
    }

    private void button2_Click(object sender, EventArgs e)
    {
        Bitmap bitmap = new Bitmap(img);

        saveJpeg(@"path", bitmap, 85L);
    }

    private void saveJpeg(string path, Bitmap img, long quality)
    {
        // Encoder parameter for image quality
        EncoderParameter qualityParam =new EncoderParameter(Encoder.Quality, quality);

        // Jpeg image codec
        ImageCodecInfo jpegCodec = getEncoderInfo("image/jpeg");

        if (jpegCodec == null)
            return;

        EncoderParameters encoderParams = new EncoderParameters(1);
        encoderParams.Param[0] = qualityParam;

        //img.Save(path, jpegCodec, encoderParams);
        img.Save(path, jpegCodec, encoderParams);
    }
    private ImageCodecInfo getEncoderInfo(string mimeType)
    {
        // Get image codecs for all image formats
        ImageCodecInfo[] codecs = ImageCodecInfo.GetImageEncoders();

        // Find the correct image codec
        for (int i = 0; i < codecs.Length; i++)
            if (codecs[i].MimeType == mimeType)
                return codecs[i];
        return null;
    }


你能帮我吗?

最佳答案

只要存在通过从文件加载图像创建的图像对象,该文件就在使用中。使用该文件时,您不能使用相同名称保存图像。

不要使用Image.FromFile加载图像,而是打开文件流并使用Image.FromStream创建图像,然后关闭文件流。这样,该文件将不再使用,您可以替换它。

09-26 05:13