java - 如何删除一个框以继续在Java中进行“for”循环？

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7年前关闭。





我是java的新手，我正在尝试编写代码，该代码生成10个随机框，然后删除一个框并添加另一个框。因此总数仍为10盒，但循环不断进行。我已经找到了如何创建10个随机框的方法，但是我不确定如何从中删除一个。这是代码：

final int width = 800;
        final int height = 600;
        final int boxWidth = 50;
        final int maxBoxes = 10;

        this.setSize(width, height);
            Random random = new Random();

                for(int box=0;box<maxBoxes;box++)
                {
                    int x = random.nextInt(width-boxWidth);
                    int y = random.nextInt(height-boxWidth);
                    GRect r = new GRect(x, y, boxWidth, boxWidth);
                    Color c = new Color(random.nextInt(256),
                                        random.nextInt(256), random.nextInt(256));
                    r.setFilled(true);
                    r.setFillColor(c);
                    this.add(r);

                    this.pause(100);

最佳答案

您需要将框值存储在数组中。然后，在循环的每次迭代中，擦除屏幕并重新绘制所有10个框。然后将一个框的框值随机替换并重复。