我是个新手。我试图从jsonDecoded变量中获取所有键。我已经尽一切所能来获取这些密钥。但是我做不到。
所以我的问题是如何以最简单,最短的方式从jsonDecoded值中获取所有密钥?
这是我的代码:
Future<String> getData() async {
var response = await http.get(
Uri.encodeFull(
"https://my-json-server.typicode.com/dipcse07/demoJSON/db"),
headers: {"Accept": "application/json"});
//print(response.body);
print('tapped');
setState(() {
data = jsonDecode(response.body.toString());
collegeDataLenght = data['CollegeName1'].length;
count = collegeDataLenght;
teachersInfo = data['CollegeName1'];
print(teachersInfo[0]['avatarImage']);
});
}
*****需要从
data
获取所有密钥**我从我的api链接获取的数据是
{
"CollegeName1":[
{
"teacherName":"Md Sazid hasan dip",
"teacherID":"2345",
"avatarImage":"url",
"address":"9/2, shenbari Road, Shanki Para Bazar Mymensingh",
"status":"Active",
"joinDate":"date",
"resignDate":"present"
},
{
"TeacherName":"Talha Azadi",
"teacherID":"2345",
"avatarImage":"url",
"address":"9/2, shenbari Road, Shanki Para Bazar Mymensingh",
"status":"Active",
"joinDate":"date",
"resignDate":"present"
}
],
"CollegeName2":[
{
"teacherName":"Md Sazid hasan dip",
"teacherID":"2345",
"avatarImage":"url",
"address":"9/2, shenbari Road, Shanki Para Bazar Mymensingh",
"status":"Active",
"joinDate":"date",
"resignDate":"present"
},
{
"TeacherName":"Talha Azadi",
"teacherID":"2345",
"avatarImage":"url",
"address":"9/2, shenbari Road, Shanki Para Bazar Mymensingh",
"status":"Active",
"joinDate":"date",
"resignDate":"present"
}
]
}
最佳答案
您解析的json将返回 Map
,它具有 .keys
属性,可以使用:
void main() {
final parsedJson = jsonDecode(json) as Map<String, dynamic>;
print(parsedJson.keys);
}