我正在检测2个div是否重叠,如果重叠,我正在检查矩形1的右侧和矩形2的左侧,矩形1的顶部和矩形2的底部等之间的距离。

    if (rect1.right > rect2.left &&
        rect1.left < rect2.right &&
        rect1.top < rect2.bottom &&
        rect1.bottom > rect2.top) {

        //collision detected.

        var dtop = Math.abs(rect1.top - rect2.bottom);
        var dbot = Math.abs(rect1.bottom - rect2.top);
        var dright =Math.abs(rect1.right - rect2.left);
        var dleft = Math.abs(rect1.left - rect2.right);
        var closestSide = Math.min(dtop,dbot,dright,dleft);

        if (closestSide == dleft || dright) {
            collisionAxis = "x";
        }

        if (closestSide == dtop || dbot) {
            collisionAxis = "y";
        }

        alert("collisionAxis: " + collisionAxis);

        return collisionAxis;

    }


由于某些原因,collisionAxis始终设置为“ y”,even when closestSide == dleft || dright,应将冲突轴设置为“ x” ...

这是一个JSFiddle示例。当白色矩形与黑色矩形碰撞时,我的collisionAxis函数中的变量DetectCollision应该设置为“ x”,因为closestSide = dright,但是以某种方式将其设置为“ y”。

谁能告诉我为什么?

最佳答案

它应该是,

    if (closestSide == dleft || closestSide == dright) {
        collisionAxis = "x";
    }

    if (closestSide == dtop || closestSide == dtopdbot) {
        collisionAxis = "y";
    }

09-26 02:28