我有
SELECT p.*, gc.*, g.*, m.*, b.*
FROM (products AS p)
LEFT JOIN merchants AS m
ON m.merchantId = p.merchantId
LEFT JOIN brands AS b
ON b.brand = p.brand
LEFT JOIN groups_content gc
ON p.brand = gc.brandsSelect
LEFT JOIN groups g
ON g.group_id = gc.group_id
WHERE `p`.`percentOff` > gc.percent_off
AND `g`.`group_active` = 1
AND `p`.`price_sale` BETWEEN gc.price_min
AND gc.price_max
AND `gc`.`group_content_id` = '180'
AND `p`.`keyword` LIKE '%women%' AND `p`.`keyword` LIKE '%jacket%'
AND `p`.`status` = 1
ORDER BY p.price_sale ASC
这给我返回158个结果
我也有
SELECT p.*, gc.*, g.*, m.*, b.*
FROM (products AS p)
LEFT JOIN merchants AS m
ON m.merchantId = p.merchantId
LEFT JOIN brands AS b
ON b.brand = p.brand
LEFT JOIN groups_content gc
ON p.brand = gc.brandsSelect
LEFT JOIN groups g
ON g.group_id = gc.group_id
WHERE `p`.`percentOff` > gc.percent_off
AND `g`.`group_active` = 1
AND `p`.`price_sale` BETWEEN gc.price_min
AND gc.price_max
AND `gc`.`group_content_id` = '180'
AND `p`.`keyword` REGEXP 'women.+jacket'
AND `p`.`status` = 1
ORDER BY p.price_sale ASC
这应该会像以前一样返回相同的结果。但只返回17个结果。我做错什么了?
----------
经过多次搜索,这里是正确的REGEXP
AND p.`keyword` REGEXP '^(.+jacket.+women.+)|^(.+women.+jacket.+).*$'
最佳答案
您的regex和like不是等价的语句:
CREATE TABLE tab(keyword VARCHAR(100));
INSERT INTO tab(keyword)
VALUES ('jacket for women');
SELECT *
FROM tab p
WHERE `p`.`keyword` LIKE '%women%' AND `p`.`keyword` LIKE '%jacket%';
-- jacket for women
SELECT *
FROM tab p
WHERE p.`keyword` REGEXP 'women.+jacket';
-- (empty)
SqlFiddleDemo
"woman"
字符串中的任意位置和"jacket"
字符串中的任意位置与。
"woman"
在开头,然后任何字符在结尾编辑:
但我该怎么做呢?“女人”在任何地方都穿线,“夹克”在任何地方
在字符串中---使用正则表达式?
一种方法是使用:
SELECT *
FROM tab
WHERE keyword REGEXP '.*women.*'
AND keyword REGEXP '.*jacket.*';
我确信这种情况存在一种正则表达式。