java - 将第二艘战舰安装到一维游戏“河战舰”中

有人能为我提供一种简单的方法，将第二个敌方战舰部署到我设计的只有一个敌人的游戏中吗，这是我目前的代码：

import java.util.*; //Scanner that reads user input

public static void main(String[] arg)
    {
        int riverLength = promptForInt("Select Length for River ") ; //Variable that stores the user input when prompted
        int [] shipArray = new int[riverLength] ; //User input is used to create an Array, i.e. River Size
        int battleshipCoordinates = new Random().nextInt(riverLength) ; //Random number is found within the Array (Where the enemy ship will hide)

        shipArray[battleshipCoordinates] = 1 ;
        boolean hit = false ; //Statement created for ship hit and default to false
        int playerSelection; //int Variable declared

        do
       {
           displayRiver (shipArray, false);
           playerSelection = promptForInt(String.format("Select location to launch torpedo (1 - %d) ", riverLength));
           playerSelection = playerSelection -1 ;

           if(shipArray[playerSelection] == 1 ) //if a user strikes the Enemy (Case 1) correctly they system informs them of a strike
           {
            System.out.println("Battleship Sunk!");
            hit = true;
            displayRiver(shipArray, true);
           }
           else if(shipArray[playerSelection] == -1)
           {
            System.out.println("Location already Hit! Try again.");
           }
           else if(shipArray[playerSelection] == 0)
           {
            System.out.println("Miss!");
            shipArray[playerSelection] = -1 ;
           }

       } while(!hit);




    }
}

最佳答案

步骤0-创建一个新的战舰，并将其放置在阵列上，就像第一个一样。

第1步-将布尔值更改为等于2的整数。

第2步-而不是切换命中率，而是在命中船只时将其降低1
数组上的该位置为0。

步骤3-调整逻辑，除非打