我需要从表中删除一些其他相似表中不可用的行。我可以使用这段代码正确选择要删除的行
SELECT *
FROM [DB01].[forward].[forward_value] as DB01
WHERE Id_forward like 'test' and
NOT EXISTS (SELECT *
FROM [DB02].[db_marketdata].[forward].[forward_value] as DB02
WHERE DB01.Id_Forward = DB02.Id_Forward and
DB01.Id_Block = DB02.Id_Block and
DB01.Id_PriceType = DB02.Id_PriceType and
)
当我将
SELECT (*)
更改为DELETE
时,出现错误,因为我无法为第一个表加上别名。消息156,第15级,状态1,第2行
关键字“ as”附近的语法不正确。
如何在不使用别名正确选择行的情况下删除这些值?
最佳答案
将您的别名使用DELETE
语法,如下所示:
delete DB01
FROM [DB01].[forward].[forward_value] as DB01
WHERE Id_forward like 'test' and
NOT EXISTS (SELECT *
FROM [DB02].[db_marketdata].[forward].[forward_value] as DB02
WHERE DB01.Id_Forward = DB02.Id_Forward and
DB01.Id_Block = DB02.Id_Block and
DB01.Id_PriceType = DB02.Id_PriceType
)