我有这段代码,无论是否找不到资源我都想抛出一个异常
Menu menu = menuService.findById(addMenuAmount.getMenuId())
.orElseThrow(com.tdk.web.exception.ResourceNotFoundException(“menu " +
addMenuAmount.getMenuId() + " not found "));
但出现编译错误:
com.tdk.web.exception cannot be resolved to a type
最佳答案
尝试此操作,并确保可访问com.tdk.web.exception.ResourceNotFoundException
Menu menu = menuService.findById(addMenuAmount.getMenuId())
.orElseThrow(() -> new com.tdk.web.exception.ResourceNotFoundException("menu " +
addMenuAmount.getMenuId() + " not found "));
注意lambda
() ->
和引号"menu "
。